In: Statistics and Probability
A financial analyst tested the performance of Portfolio A against the S&P500 Index during 150 months of transactions. The figure below shows part of the output from a regression between the two sets of returns.
ANOVA | |||
df | SS | MS | |
Regression | 1 | 0.080 | 0.080 |
Residual | 120 | 0.107 | 0.000 |
Total | 121 | 0.187 | |
Coefficients | Standard Error | ||
Intercept | -0.001 | 0.003 | |
S&P500 | 0.346 | 0.037 |
What is the estimated equation that corresponds to these results?Find the R2 and provide a brief explanation about the meaning of yourresult.Find the t-statistic for the coefficient of the intercept and of the variableS&P500.Give a 95% confidence interval for the coefficient for the variable S&P500. What return for the Portfolio A would be expected if S&P500’s returnwas 2.5%?
estimated equation is Y^ = -0.001 + 0.346*S&P500
R² = SSR/SST = 0.080/0.187 = 0.4278
about 42.78% of variation in observation of return for portfolio A is explained by variable S&P500
t-statistic for the coefficient of the intercept = -0.001/0.003= -0.33333
t-statistic for the coefficient of the variableS&P500 =
0.346/0.037= 9.351351351
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confidence interval for slope
n = 122
alpha,α = 0.05
estimated slope= 0.346
std error = 0.037
Df = n-2 = 120
t critical value = 1.9799 [excel function:
=t.inv.2t(α,df) ]
margin of error ,E = t*std error = 1.9799
* 0.037 = 0.07326
95% confidence interval is ß1 ± E
lower bound = estimated slope - margin of error =
0.346 - 0.0733 =
0.273
upper bound = estimated slope + margin of error =
0.346 + 0.0733 =
0.419
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Y^ = -0.001 + 0.346*S&P500
S&P500’s return = 2.5%
return for the Portfolio A = -0.001 + 0.346*2.5 = 0.864
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