In: Statistics and Probability
Problem 2: Speeding in a construction zone Please type the answer. Thank you.
A group of Brigham Young University—Idaho students collected data on the speed of vehicles traveling through a construction zone on a state highway, where the speed was 25 mph. The recorded speed (in mph) of 14 randomly selected vehicles is given below:
20,24,27,28,29,30,32,33,34,36,38,39,40,40
solution:-
given data = 20,24,27,28,29,30,32,33,34,36,38,39,40,40
mean = 32.1429
standard deviation = 6.1751
degree of freedom df = n - 1 = 14 - 1 = 13
=> 95% confidence interval
we look into t table with df = 13 and with 95% confidence
critical value t = 2.160
confidence interval formula
mean +/- t * standard deviation/sqrt(n)
32.1429 +/- 2.160 * 6.1751/sqrt(14)
(28.5781 , 35.7077) (rounded to four decimals)
=> 99% confidence interval
we look into t table with df = 13 and with 99% confidence
critical value t = 3.012
confidence interval formula
mean +/- t * standard deviation/sqrt(n)
32.1429 +/- 3.012 * 6.1751/sqrt(14)
(27.1720 , 37.1138) (rounded to four decimals)
=> the widths of the 95% and 99% confidence intervals
width = (upper confidence - lower confidence)
width of 95% confidence
(35.7077-28.5781) = 7.1
width of 99% confidence
(37.1138-27.1720) = 9.9
the 99% confidence is wider
=> conclusions do you draw about the speeds people drive in this
construction zone
here to believe that the mean speed of drivers in this area exceeds the posted speed limit