Question

For each situation, perform a hypothesis test for the population mean. Be sure to show the null hypothesis H0, the alternative hypothesis H1, the P-level you get from TTest, the result of the test (i.e. reject / do not reject H0) and the conclusion (interpret the result in English).

A Jedi sage would like proof that Jedi trainees have a higher level of midichlorians than non-Jedis. Non-Jedis have a mean midichlorian level of 2500. A random sample of 25 Jedi trainees have a sample mean midichlorian level of 2875, with a sample standard deviation of 1050. Is this adequate evidence at the α = 0.05 level of certainty that Jedi trainees have higher midichlorian levels than non-Jedis?

H0:

H1:

P-level:

Result:

Conclusion:

Answer 1

Solution :

Given that,

= 2875

= 2500

s = 1050

n = 25

df = n - 1 = 25 - 1 = 24

This is the two tailed test .

The null and alternative hypothesis is ,

H₀ :   2500

H_a : > 2500

Test statistic = t = ( - ) / s / n = (2875 - 2500) / 1050 / 25 = 1.7857

This is the right tailed test .

P-value = 0.0434

= 0.05

P-value <

Reject the null hypothesis .

This is an adequate evidence at the α = 0.05 level of certainty that Jedi

trainees have higher midichlorian levels than non-Jedis .