In: Mechanical Engineering
Calculate the magnitude of the moment about the base point O of the 600Nforce in five different ways.
Solution
1. By M = F*d the moment is clockwise and has the magnitude
The moment arm to the 600-N force is:
d = 4 cos 40+ 2 sin 40= 4.35 m
Mo = 600(4.35) = 2610 N.m clockwise
2. By Varignon’s theorem,
F1 = 600 cos 40= 460 N,
F2 = 600 sin 40= 386 N
Mo= 460(4) +386(2) = 2610 N.m clockwise
3. By the principle of transmissibility, move the 600N force along its line of action to point B, which eliminates the moment of the component F2.
d1 = 4 + 2 tan 40= 5.68 m
Mo=460(5.68)=2610 N.m clockwise
5. By the vector expression for a moment