Question

In: Civil Engineering

An existing unlined channel is having the following dimensions: Bottom width = 1.52 m; Side slopes...

An existing unlined channel is having the following dimensions:

Bottom width = 1.52 m; Side slopes = 1:1; Flow depth = 0.90meter; and

Bed-slope = 1/1667.

It is proposed to line this channel for the same discharging capacity. Find out the dimensions of the lined channel and work out the economics of the concrete lining, if following data are given:

Length of irrigation season = 150 days;

Saving in seepage loss by lining the canal = 1.5 per cent per km

Cost of water = Rs.150 /ha/m; Cost of concrete lining = Rs.16 /sq. m

Cost of reshaping and trimming canal = Rs. 4.00 per sq. m.

Life of lining = 40 years; Interest rate = 7 percent.

Annual maintenance and operational cost (rupees per km per year)

for unlined canals earth = Rs.1000; for concrete lined canals = Rs. 200

Other additional benefits = Rs. 350.00

Assume any other necessary data, if not given.

Solutions

Expert Solution

where all notations have their usual meaning. Please give positive feedback. Thank you


Related Solutions

Compute the normal depth (y) in a trapezoidal channel having a bottom-width 10 m, side slopes...
Compute the normal depth (y) in a trapezoidal channel having a bottom-width 10 m, side slopes 1H to 1V and carrying a flow of 30 m3/s. The slope of the channel bottom is So = 0.001 and n = 0.013. A. B. C. D.  
B. A trapezoidal channel with a bottom width of 4 m and side slopes 4H: 1V...
B. A trapezoidal channel with a bottom width of 4 m and side slopes 4H: 1V carries a discharge of 30 m3 /s. The channel has bed slope= 0.1 % and manning roughness coefficient = 0.015. Determine the following: i. the minimum specific energy ii. the normal depth iii. the critical slope iv. state of the flow in the channel
A trapezoidal channel having bottom width 6m ,side slopes 2 horizontal to 1 vertical ,Mannings n=...
A trapezoidal channel having bottom width 6m ,side slopes 2 horizontal to 1 vertical ,Mannings n= 0.025 and bottom slope 0.016 ,carries a discharge of 10 m3/sec . Compute the back water profile created by the dam which backs up the water to a depth of 2.0 m immediately behind the dam ((Direct method if it is possible))
A trapezoidal channel having bottom width 6m ,side slopes 2 horizontal to 1 vertical ,Manning’s n=...
A trapezoidal channel having bottom width 6m ,side slopes 2 horizontal to 1 vertical ,Manning’s n= 0.025 and bottom slope 0.016 ,carries a discharge of 10 m3/sec . Compute the back water profile created by the dam which backs up the water to a depth of (3) immediately behind the dam.                                                                [ 5 Marks ] ( THIS SHOULD BE DONE USING EXCEL SHEET )
A trapezoidal channel has size slopes of 3:1 (H:V), a bottom width of 22 feet, a...
A trapezoidal channel has size slopes of 3:1 (H:V), a bottom width of 22 feet, a longitudinal slope of 0.0003, a Manning’s roughness coefficient of 0.023, and carries a flow rate of 340 cfs. a) Calculate the normal depth in this channel. b) Calculate the normal specific energy. c) Calculate the Froude number. State the classification of flow. d) State how the critical depth will compare to the normal depth and why.
A road of formation width 12 m is to be constructed with side slopes of 1...
A road of formation width 12 m is to be constructed with side slopes of 1 vertical to 2 horizontal in cut and 1 vertical to 3 horizontal in fill. The existing ground surface has a cross fall of 1 vertical to 8 horizontal and it will intersect the formation 1.5 m to the left of the center line and 1.0 m to the right of the center line at two cross sections 20 m apart. Calculate the areas related...
)An embankment of width 15 m and side slopes 2:1 is required to make on a...
)An embankment of width 15 m and side slopes 2:1 is required to make on a ground, which is level in a direction transverse to the centerline. The central heights at 50 m intervals are as follows: 1.70, 2.25, 3.15, 4.50, 2.75, 2.15, and 1.95. Calculate the volume of earthwork according to Trapezoidal formula, and prismoidal formula.
A highway embankment of formation width of 15 m and side slopes 1.5:1 is to be...
A highway embankment of formation width of 15 m and side slopes 1.5:1 is to be constructed. The ground level along the centerline is as follows in Table below. The embankment has a rising gradient of 1 in 200, and the formation level at zero chainage is 115.00. Assuming the ground is level across the centerline; compute the volume of earthwork. Chainage 0 50 100 150 200 250 GL (m) 115.75 114.35 116.80 115.20 118.50 118.25
A trapezoidal channel has a bottom width of 3.25 m and sides with a slope of...
A trapezoidal channel has a bottom width of 3.25 m and sides with a slope of 1 vertical to 1.5 horizontal. The slope of the bed is 1 in 2000 and the depth of water is 1.2 m. a) Using the Manning Formula with n = 0.025, calculate the velocity and the discharge rate of the flow. b) Calculate the Chezy number for the channel and use that to re- calculate the velocity and the discharge rate of the flow....
A trapezoidal channel carrying 280 cfs has a bottom width of 12 ft, side slope of...
A trapezoidal channel carrying 280 cfs has a bottom width of 12 ft, side slope of 2 and a longitudinal bottom slope of 0.001. The critical depth is 2.25 ft and the normal depth is 2.78. The flow depth at the downstream end of this channel is 3.12 ft. Determine which of the statements below is correct. Select one: a. The flow depth decreases in the flow direction. b. None of the above. c. A flow depth of 2.55 ft...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT