Question

In: Statistics and Probability

Among a random group of 36 students, the average time spent daily on telephone calls was...

Among a random group of 36 students, the average time spent daily on telephone calls was found to
be 20 minutes. Assuming that the amount of time spent daily on telephone calls by a student is a
random variable with distribution N(µ; 25), calculate the confidence interval for the mean duration,
assuming a confidence level of 0.88. How many students should be interrogated, in order to obtain a
confidence interval for the mean of length not exceeding 2, with a confidence level of 0.99?

Solutions

Expert Solution


Related Solutions

Among a random group of 36 students, the average time spent daily on telephone calls was...
Among a random group of 36 students, the average time spent daily on telephone calls was found to be 20 minutes. Assuming that the amount of time spent daily on telephone calls by a student is a random variable with distribution N(µ; 25), calculate the confidence interval for the mean duration, assuming a confidence level of 0.88. How many students should be interrogated, in order to obtain a confidence interval for the mean of length not exceeding 2, with a...
In studying the relationship between average daily temperature and time spent on a telephone, suppose you...
In studying the relationship between average daily temperature and time spent on a telephone, suppose you computed r=0.607 using n=31 data points. Using the critical values table below, determine if the value of r is significant or not.
The average time spent sleeping​ (in hours) for a group of medical residents at a hospital...
The average time spent sleeping​ (in hours) for a group of medical residents at a hospital can be approximated by a normal​ distribution, as shown in the graph to the right. Answer parts​ (a) and​ (b) below. mu equals 5.4 hours sigma equals 1.2 hour A graph titled "Sleeping Times of Medical Residents" has a horizontal axis labeled "Hours" from 1 to 10 in increments of 1. A normal curve labeled mu = 5.4 hours and sigma = 1.2 hour...
The average time spent sleeping​ (in hours) for a group of medical residents at a hospital...
The average time spent sleeping​ (in hours) for a group of medical residents at a hospital can be approximated by a normal​ distribution, as shown in the graph to the right. Answer parts​ (a) and​ (b) below. mu equals 5.4 hours sigma equals 1.2 hour A graph titled "Sleeping Times of Medical Residents" has a horizontal axis labeled "Hours" from 1 to 10 in increments of 1. A normal curve labeled mu = 5.4 hours and sigma = 1.2 hour...
Homer is studying the relationship between the average daily temperature and time spent watching television and...
Homer is studying the relationship between the average daily temperature and time spent watching television and has collected the data shown in the table. The line of best fit for the data is yˆ=−0.6x+94.5. Assume the line of best fit is significant and there is a strong linear relationship between the variables. Temperature (Degrees) 40506070 Minutes Watching Television 70655952 (a) According to the line of best fit, what would be the predicted number of minutes spent watching television for an...
A random sample of 25 CCRI students found that the average amount spent on textbooks for...
A random sample of 25 CCRI students found that the average amount spent on textbooks for a course was $180 with a standard deviation of $30. Find a 95% 2-tailed confidence interval for the population mean (μ) of the amount a CCRI student spends on textbooks.
The average time spent sleeping (in hours) for a group of healthy adults can be approximated...
The average time spent sleeping (in hours) for a group of healthy adults can be approximated by a normal distribution with a mean of 6.5 hours and a standard deviation of 1 hour. Between what two values does the middle 70% of the sleep times lie? 5.218 and 7.782 5.464 and 7.536 5.658 and 7.342 4.855 and 8.145
A recent survey of 31 students reported that the average amount of time they spent listening...
A recent survey of 31 students reported that the average amount of time they spent listening to music was 11.5 hours per week, with a sample standard deviation of 9.2 hours. Which of the following is a 90% confidence interval for the mean time per week spent listening to the radio? Is this confidence interval for a population mean or population proportion? When do you use a z-test and when do you use a t-test?
A telephone company claims that the service calls which they receive are equally distributed among the...
A telephone company claims that the service calls which they receive are equally distributed among the five working days of the week. A survey of 110 randomly selected service calls was conducted. Is there enough evidence to refute the telephone company's claim that the number of service calls does not change from day-to-day? Days of the Week Mon Tue Wed Thu Fri Number of Calls 24 26 17 20 23 Copy Data Step 2 of 10: What does the null...
A telephone company claims that the service calls which they receive are equally distributed among the...
A telephone company claims that the service calls which they receive are equally distributed among the five working days of the week. A survey of 110 randomly selected service calls was conducted. Is there enough evidence to refute the telephone company's claim that the number of service calls does not change from day-to-day? Days of the Week Mon Tue Wed Thu Fri Number of Calls 24 28 21 26 11 Step 3 of 9: State the null and alternative hypothesis...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT