Question

In: Statistics and Probability

The average time spent sleeping​ (in hours) for a group of medical residents at a hospital...

The average time spent sleeping​ (in hours) for a group of medical residents at a hospital can be approximated by a normal​ distribution, as shown in the graph to the right. Answer parts​ (a) and​ (b) below.
mu equals 5.4 hours sigma equals 1.2 hour
A graph titled "Sleeping Times of Medical Residents" has a horizontal axis labeled "Hours" from 1 to 10 in increments of 1. A normal curve labeled mu = 5.4 hours and sigma = 1.2 hour is over the horizontal axis and is centered on 5.4.

What is the shortest time spent sleeping that would still place a resident in the top​ 5% of sleeping​ times?
Residents who get at least __  hours of sleep are in the top​ 5% of sleeping times.
​(Round to two decimal places as​ needed.)
​(b) Between what two values does the middle​ 50% of the sleep times​ lie?
The middle​ 50% of sleep times lies between __ hours on the low end and __ hours on the high end. ​(Round to two decimal places as​ needed.)

Solutions

Expert Solution

from Z-table, Lookup fro Z-value corresponding to area 0.05 to the right of the normal curve.

----------------------------------------------------------------------------------------------------------------------------------

​​​​​​​

Assume the mean to be symmetrically distributed

from Z-table, Lookup fro Z-value corresponding to area 0.25 to the left of the normal curve.

from Z-table, Lookup fro Z-value corresponding to area 0.25 to the right of the normal curve.

​​​​​​​


Related Solutions

The average time spent sleeping​ (in hours) for a group of medical residents at a hospital...
The average time spent sleeping​ (in hours) for a group of medical residents at a hospital can be approximated by a normal​ distribution, as shown in the graph to the right. Answer parts​ (a) and​ (b) below. mu equals 5.4 hours sigma equals 1.2 hour A graph titled "Sleeping Times of Medical Residents" has a horizontal axis labeled "Hours" from 1 to 10 in increments of 1. A normal curve labeled mu = 5.4 hours and sigma = 1.2 hour...
The average time spent sleeping per night for a group of medical residents is 6.1 hours...
The average time spent sleeping per night for a group of medical residents is 6.1 hours with a standard deviation of 1.0 hour. Between what two values do the middle 50% of the sleep times fall?
The average time spent sleeping (in hours) for a group of healthy adults can be approximated...
The average time spent sleeping (in hours) for a group of healthy adults can be approximated by a normal distribution with a mean of 6.5 hours and a standard deviation of 1 hour. Between what two values does the middle 70% of the sleep times lie? 5.218 and 7.782 5.464 and 7.536 5.658 and 7.342 4.855 and 8.145
Is the average amount of time spent sleeping each day different between male and female students?...
Is the average amount of time spent sleeping each day different between male and female students? Which hypothesis test is the most appropriate to use in this problem? Why? (Note: if you are doing a 2-sample t-test, make sure you state which one you are doing and why.) If the test you chose has a t-statistic, report it here with degrees of freedom. If it does not, state that the test you chose does not have a test-statistic. Give and...
A researcher is interested in studying average hours per year spent on continuous medical education by...
A researcher is interested in studying average hours per year spent on continuous medical education by physicians in a large hospital system. The data is limited to demographics (age, race, gender), professional characteristics (years worked in the field, specialty) and self-reported hours of CME. What is the independent variable? What is the dependent variable? Is the dependent variable continuous or categorical? Is the independent variable(s) continuous or categorical?
Among a random group of 36 students, the average time spent daily on telephone calls was...
Among a random group of 36 students, the average time spent daily on telephone calls was found to be 20 minutes. Assuming that the amount of time spent daily on telephone calls by a student is a random variable with distribution N(µ; 25), calculate the confidence interval for the mean duration, assuming a confidence level of 0.88. How many students should be interrogated, in order to obtain a confidence interval for the mean of length not exceeding 2, with a...
Among a random group of 36 students, the average time spent daily on telephone calls was...
Among a random group of 36 students, the average time spent daily on telephone calls was found to be 20 minutes. Assuming that the amount of time spent daily on telephone calls by a student is a random variable with distribution N(µ; 25), calculate the confidence interval for the mean duration, assuming a confidence level of 0.88. How many students should be interrogated, in order to obtain a confidence interval for the mean of length not exceeding 2, with a...
A sample of 83 women found that the mean length of time they spent sleeping daily...
A sample of 83 women found that the mean length of time they spent sleeping daily was 7.0 hours with standard deviation 1.8 hours. An independent sample of 65 men found that the mean length of time they spent sleeping daily was 6.6 hours with standard deviation 1.7 hours. At the 5% level of significance, can we show women sleep more on average than men? (a) Do an appropriate test. State conclusions. (b) Find the p-value of the test.
A recent article found that Massachusetts residents spent an average of $860.70 on the lottery in...
A recent article found that Massachusetts residents spent an average of $860.70 on the lottery in 2010, more than three times the U.S. average (http://www.businessweek.com, March 14, 2012). A researcher at a Boston think tank believes that Massachusetts residents spend significantly less than this amount. He surveys 100 Massachusetts residents and asks them about their annual expenditures on the lottery. a. Specify the competing hypotheses to test the researcher’s claim. b. Specify the critical value(s) of the test at the...
An article found that Massachusetts residents spent an average of $860.70 on the lottery in 2010,...
An article found that Massachusetts residents spent an average of $860.70 on the lottery in 2010, more than three times the U.S. average (www.businessweek.com, March 14, 2012). A researcher at a Boston think tank believes that Massachusetts residents spend less than this amount. He surveys 100 Massachusetts residents and asks them about their annual expenditures on the lottery. Expenditures 790 594 899 1105 1090 1197 413 803 1069 633 712 512 481 654 695 426 736 769 877 777 785...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT