A platinum sphere with radius 0.0161 m is totally immersed in mercury.The densities of platinum and...

A platinum sphere with radius 0.0161 m is totally immersed in mercury.The densities of platinum and mercury are 2.14*10^4 kg/m3 and 1.36*10^4 kg/m3, respectively.

Find the weight of the sphere, the buoyant force acting on the sphere, and the sphere\'s apparent weight.

Expert Solution

Radius of sphere, r=0.0161 m

Volume of sphere, V=(4/3)*pi*r³

=(4/3)*3.14*0.0161³=1.75*10^-5 m³

Weight of sphere=Volume*density of sphere*g

=1.75*10^-5*2.14*10⁴*9.8

=3.67 N

Buoyant force= Volume*density of mercury*g

=1.75*10^-5*1.36*10⁴*9.8

=2.33 N

Apparent of sphere=Volume*(density of sphere-density of mercury)*g

=1.75*10^-5*(2.14*10⁴-1.6*10^-4) 9.8

=1.34 N

genius_generous answered 4 months ago

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