A certain dynamical system is governed by the equation
x'' + (x')2 + x = 0....
A certain dynamical system is governed by the equation
x'' + (x')2 + x = 0. Show that the origin is
a center in the phase plane and that open and closed paths are
separated by the path
The motion of an harmonic oscillator is governed by the
differential equation 2¨x + 3 ˙x + 4x = g(t).
i. Suppose the oscillator is unforced and the motion is started
from rest with an initial displacement of 5 positive units from the
equilibrium position. Will the oscillator pass through the
equilibrium position multiple times? Justify your answer.
ii. Now suppose the oscillator experiences a forcing function 2e
t for the first two seconds, after which it is removed. Later,...
Consider the differential equation x′=[2 4
-2 −2],
with x(0)=[1 1]
Solve the differential equation where x=[x(t)y(t)].
x(t)=
y(t)=
please be as clear as possible especially when solving for c1
and c2 that's the part i need help the most
The only solution to the equation x^2 − xy + y^2 = 0 is the
origin. Prove that statement is
true by converting to polar coordinates. To be clear, you need to
show two things:
a. The origin is a solution to the equation (easy).
b. There is no other point which is a solution to the equation (not
easy).
Consider the equation: ?̇ +2? = ?(?) with initial condition x(0)
= 2
(a) If u(t) = 0, find the solution ?(?). What is ?(?) as t ->
∞?
(b) If u(t) = 4+t, find the solution ?(?). What is ?(?) as t
-> ∞?
(c) If u(t) = ?3?, find the solution ?(?). What is
?(?) as t -> ∞?
(d) If u(t) = δ(t), find the solution ?(?). What is ?(?) as t
-> ∞?
Consider the nonlinear equation f(x) = x3−
2x2 − x + 2 = 0.
(a) Verify that x = 1 is a solution.
(b) Convert f(x) = 0 to a fixed point equation g(x) = x where
this is not the fixed point iteration implied by Newton’s method,
and verify that x = 1 is a fixed point of g(x) = x.
(c) Convert f(x) = 0 to the fixed point iteration implied by
Newton’s method and again verify that...
For
the differential equation (2 -x^4)y" + (2*x -4)y' + (2*x^2)y=0.
Compute the recursion formula for the coefficients of the power
series solution centered at x(0)=0 and use it to compute the first
three nonzero terms of the solution with y(0)= 12 , y'(0) =0
Consider the equation x^2+(y-2)^2 and the relation “(x, y) R (0,
2)”, where R is read as “has distance 1 of”. For example, “(0, 3) R
(0, 2)”, that is, “(0, 3) has distance 1 of (0, 2)”. This relation
can also be read as “(x, y) belongs to the circle of radius 1 with
center (0, 2)”. In other words: “(x, y) satisfies this equation if,
and only if, (x, y) R (0, 2)”. Does this equation determine a...