In: Chemistry
The vaporization of 1 mole of liquid water (the system) at 100.9°C, 1.00 atm, is endothermic.
Assume at exactly 100.0°C and 1.00 atm total pressure, 1.00 mole of liquid water and 1.00 mole of water vapor occupy 18.80 mL and 30.62 L, respectively.
H20 (l) +40.7kJ ----> H20 (g)
Please answer both parts of the question:
1. Calculate the work done on or by the system when 3.45 mol of liquid H2O vaporizes.
2. Calculate the water's change in internal energy.