The proportion of observations from a standard Normal distribution that take values greater than 1.631.63 is...

The proportion of observations from a standard Normal distribution that take values greater than 1.631.63 is about (±±0.001)

Expert Solution

Using standard normal z-table we find, the proportion of observations that take values greater than 1.63.

That is to find, P(Z > 1.63)

P(Z > 1.63) = 1 - P(Z < 1.63) = 1 - 0.9484 = 0.0516

=> P(Z > 1.63) = 0.0516

Therefore, required proportion is 0.0516

orchestra answered 2 years ago

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