Question

In: Physics

Problem A big box of mass m1 sits on the flat surface. There is no friction...

Problem A big box of mass m1 sits on the flat surface. There is no friction between this box and the surface. A small box with mass m2 sits on top of the big one. There is friction between two boxes and the friction coefficient is µ. A force F is applied to the big box in the horizontal direction to the right. What is the maximum value of F that can be applied so that the upper box does not slide back during the motion? Acceleration of gravity is g.

Solutions

Expert Solution

In this problem the upper box does not slide back means it will move together with the bigger box with same acceleration.Here we will use the concept of frictional force and Newton's 2nd law of motion.


Related Solutions

A block of mass m1 = 0.500 kg sits on a frictionless surface and is connected...
A block of mass m1 = 0.500 kg sits on a frictionless surface and is connected by a weightless string to a weight of mass m2 = 0.200 kg that hangs from a pulley. The system is initially at rest. If the mass m2 is released and drops for 1.00 m, what is the speed of the system? Assume that mass m1 does not reach the edge of the surface. Use energy considerations, not force considerations. What is the speed...
A mass; m1 = 64 g, sits on a frictionless horizontal surface, and is attached to...
A mass; m1 = 64 g, sits on a frictionless horizontal surface, and is attached to a spring of spring constant k = 51 N/m. The other end of the horizontal spring is attached to a wall; the system is in equilibrium. Another mass; m2 = 18 g, strikes the stationary mass m1, and sticks to it. As a result, the spring is compressed by a distance of 24.5 cm before the masses come to a momentary stop. a) How...
A block sits on a flat horizontal surface. The block's mass is 100kg. The coefficient of...
A block sits on a flat horizontal surface. The block's mass is 100kg. The coefficient of static friction is 0.3. The coefficient of kinetic friction is 0.25. Find whatis the friction cone angle between the two surfaces in degree?
The coefficient of friction between the block of mass m1 = 3.00 kg and the surface...
The coefficient of friction between the block of mass m1 = 3.00 kg and the surface in the figure below is μk = 0.455. The system starts from rest. What is the speed of the ball of mass m2 = 5.00 kg when it has fallen a distance h = 1.10 m?
A box of mass 18.0 kg sits at rest on a horizontal surface. The coefficient of...
A box of mass 18.0 kg sits at rest on a horizontal surface. The coefficient of kinetic friction between the surface and the box is 0.300. The box is initially at rest, and then a constant force of magnitude FF and direction 39.0 ∘∘ below the horizontal is applied to the box; the box slides along the surface. A. What is F if the box has a speed of 6.00 m/s after traveling a distance of 8.00 mm? Express your...
A block with the mass M slides with no friction on a horizontal surface (no friction)...
A block with the mass M slides with no friction on a horizontal surface (no friction) with speed x when it collides and sticks to the second block with also mass M that is attached to a third block with mass M via an ideal spring with spring constant k. Before collision, spring has its natural length and the blocks attached to it are at rest. Find an expression for the maximum kinetic energy of the third block post collision...
A gymnast with mass m1 = 42 kg is on a balance beam that sits on...
A gymnast with mass m1 = 42 kg is on a balance beam that sits on (but is not attached to) two supports. The beam has a mass m2 = 112 kg and length L = 5 m. Each support is 1/3 of the way from each end. Initially the gymnast stands at the left end of the beam. 1) What is the force the left support exerts on the beam? N   2) What is the force the right support...
A box of mass sits on the floor of an elevator. The area of the bottom...
A box of mass sits on the floor of an elevator. The area of the bottom surface of the box is 0.250 m2. When the elevator is moving upward at a constant speed of 2.00 m/s the pressure the box exerts on the floor is 981 pascal. (Note: One Pascal equals one Newton per square meter; 1 Pa = 1 N/m2). Calculate the pressure the box exerts on the floor while the elevator a. slows uniformly from an upward speed...
A box of weight 120 N sits on a level surface. It is initially at rest....
A box of weight 120 N sits on a level surface. It is initially at rest. The coefficient of kinetic friction is 0.30 and the coefficient of static friction is 0.50. A person goes up to the box and pushes horizontally with a force of 45 N. What is the force of friction acting on the box during the push?
A box rests on top of a flat bed truck. The box has a mass of...
A box rests on top of a flat bed truck. The box has a mass of m = 23 kg. The coefficient of static friction between the box and truck is μs = 0.87 and the coefficient of kinetic friction between the box and truck is μk = 0.68. 1)The truck accelerates from rest to vf = 18 m/s in t = 15 s (which is slow enough that the box will not slide). What is the acceleration of the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT