Question

THIS IS FOR DEVC++. I use the 5.11 version

Write a program to take input of scores for Chemistry, Biology and English for a student and display the average with 2 decimal places if all of the three scores are in the range between 1 and 100 inclusive. Program should also display the course name for which scores are entered out of range telling Average couldn't be calculated.

Following is a sample run:

Enter scores for Chemistry, Biology and English between 1 and 100:
45
89
96
Avg score is 76.67

Following is another sample run:

Enter scores for Chemistry, Biology and English between 1 and 100:
900
78
89
Average cannot be calculated because Chemistry Scores were not in range.

Following is another sample run:

Enter scores for Chemistry, Biology and English between 1 and 100:
89
767
8787
Average cannot be calculated because Biology Scores were not in range.
Average cannot be calculated because English Scores were not in range.

Following is another sample run:

Enter scores for Chemistry, Biology and English between 1 and 100:
87
90
-1
Average cannot be calculated because English Scores were not in range.

Answer 1

Answer-

your code is here-

#include <stdio.h>

int main()
{
float chm, bio, eng;
float total, average;
printf("Enter scores for Chemistry, Biology and English between 1 and 100:\n");
scanf("%f%f%f", &chm,&bio, &eng);

if(chm<1 || chm>100 )
{
   printf("Average cannot be calculated because Chemistry Scores were not in range.\n");
}

if(bio<1 || bio>100 )
{
   printf("Average cannot be calculated because Biology Scores were not in range.\n");
}
if(eng<1 || eng>100 )
{
   printf("Average cannot be calculated because English Scores were not in range.\n");
}
if(chm>=1 && chm<=100 && bio>=1 && bio<=100 && eng>=1 && eng<=100 )
{

total = eng + bio + chm ;
average = total / 3.0;
printf("Avg score is = %.2f\n", average);
}

return 0;
}

some screenshot of running output as your requirement-

Note- Please do upvote, if any problem then comment in box sure I will help.