Question

In: Statistics and Probability

The heights were recorded for a Simple Random Sample of 270 junior.  The mean of this sample...

The heights were recorded for a Simple Random Sample of 270 junior.  The mean of this sample was 66.5 inches.  The heights are known to be Normally Distributed with a population standard deviation of 5.1 inches. (You do not need a data set for this). Test the claim that the mean height of Juniors has increased from 65.7 at a 0.01 significance level. (Use MINITAB to do the hypothesis test and copy and paste the output of the hypothesis test here (0.5pts). Then answer a-h based on that output.):

  1. (2) State the null and alternative hypothesis using the correct symbols and values.

(examples: H0: m = m0 vs. Ha: m < m0  or H0: p = p0 vs. Ha: p ≠ p0 )

  1. (0.5)State the significance level.
  2. (0.5)State the test statistic.
  3. (0.5)State the p-value.
  4. (1) State whether you reject or do not reject the null hypothesis.
  5. (1)State the critical value(s).
  6. (3)Give your conclusion in the context of the problem.  (If you say something like I reject the null or do not reject the null you will receive no credit)
  7. (0.5)If the mean height of Juniors has not changed, did you make an error, and if so, which one?

Solutions

Expert Solution

H0 : Mu = 65.7

H1 : Mu > 65.7

Significance level = 0.01

Test statistics = 2.58

P value = 0.005

As p value < 0.01

We reject the null hypothesis.

Critical Value = 2.33

As we reject the null hypothesis at 1% level of significance, we conclude that the claim is true that the mean height of Juniors has increased from 65.7.

Here, correct error is type I error.

Dear student,
I am waiting for your feedback. I have given my 100% to solve your queries. If you satisfied with my answer then please please like this.
Thank You


Related Solutions

A random sample of 18 women is taken and their heights were recorded. The heights (in...
A random sample of 18 women is taken and their heights were recorded. The heights (in inches) are: 60, 62, 63, 63, 63, 66, 66, 66, 66, 67, 67, 68, 68, 68, 69, 70, 71, 71 Assume that women’s height are normally distributed. Let μ be the mean height of all women and let p be the proportion of all women that are taller than 54 inches. a) Test the hypothesis H0: μ = 54 against H1: μ > 54....
Suppose a simple random sample of athletes in the NBA heights is taken. There were 28...
Suppose a simple random sample of athletes in the NBA heights is taken. There were 28 athletes in the sample with a mean height of 78.4 inches and standard deviation of 2 inches. It has been confirmed through statistical analysis that NBA player heights follows a normal distribution. a. what parameter are we estimating? b. Explain the requirements as they relate to the problem c.What is the point estimate of the parameter? d.Input the margin of error for a 95%...
When birth weights were recorded for a simple random sample of 16 male babies born to...
When birth weights were recorded for a simple random sample of 16 male babies born to mothers taking a special vitamin supplement, the sample had a mean of 3.675 kilograms and a standard deviation of 0.657 kilogram. The birth weights for all babies are assumed to normally distributed. Use a 0.05 significance level to test the claim that the mean birth weight for all male babies of mothers taking the vitamin supplement is different from 3.39 kilograms, which is the...
The heights of a simple random sample of soccer players in a particular league are given...
The heights of a simple random sample of soccer players in a particular league are given below. Can you conclude at the 5% level of significance, that the average height of soccer players in the league sampled is over 182 cm? Assume that the heights of soccer players is normal. Show all of your work, include all necessary steps, and be complete in your answer and explanation. 193 190 185.3 193 172.7 180.3 186 188
The heights of a simple random sample of 400 male high school sophomores in a Midwestern...
The heights of a simple random sample of 400 male high school sophomores in a Midwestern state are measured. The sample mean is = 66.2 inches. Suppose that the heights of male high school sophomores follow a Normal distribution with a standard deviation of σ = 4.1 inches. What is a 95% confidence interval for µ? A. (59.46, 72.94) B. (58.16, 74.24) C. (65.80, 66.60) D. (65.86, 66.54)
The resting pulse rate of a simple random sample of 9 women was recorded yielding a...
The resting pulse rate of a simple random sample of 9 women was recorded yielding a mean resting pulse rate of 76 beats per minute with standard deviation 5. Use this information for this question and the next one. The p-value of a statistical test where the alternative hypothesis is that the mean resting pulse rate is greater than 72 is: (a) Between 0 and 0.01 (b) Between 0.01 and 0.025 (c) Between 0.025 and 0.05 (d) Between 0.05 and...
A simple random sample of size n is drawn. The sample​ mean is found to be...
A simple random sample of size n is drawn. The sample​ mean is found to be 17.6​, and the sample standard​ deviation, s, is found to be 4.7. A). Construct a 95​% confidence interval about if the sample​ size, n, is 51.
A simple random sample of size n is drawn. The sample​ mean is found to be...
A simple random sample of size n is drawn. The sample​ mean is found to be 17.6​, and the sample standard​ deviation, s, is found to be 4.7. Construct a 99​% confidence interval about if the sample​ size, n, is 34.
A simple random sample of n = 54 provided a sample mean of 22.5 and a...
A simple random sample of n = 54 provided a sample mean of 22.5 and a sample standard deviation of 4.4. Develop a 90% confidence interval for the population mean. (Round to two decimal places) __________and__________ Develop a 95% confidence interval for the population mean. (Round to two decimal places) __________and__________ Develop a 99% confidence interval for the population mean. (Round to two decimal places) __________and__________
A simple random sample with n = 56 provided a sample mean of 29.5 and a...
A simple random sample with n = 56 provided a sample mean of 29.5 and a sample standard deviation of 4.4. A. Develop a 90% confidence interval for the population mean. B. Develop a 95% confidence interval for the population mean. C. Develop a 99% confidence interval for the population mean.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT