Question

In: Statistics and Probability

The heights of a simple random sample of 400 male high school sophomores in a Midwestern...

The heights of a simple random sample of 400 male high school sophomores in a Midwestern state are measured. The sample mean is = 66.2 inches. Suppose that the heights of male high school sophomores follow a Normal distribution with a standard deviation of σ = 4.1 inches. What is a 95% confidence interval for µ?

  • A. (59.46, 72.94)
  • B. (58.16, 74.24)
  • C. (65.80, 66.60)
  • D. (65.86, 66.54)

Solutions

Expert Solution

= Solution :


Given that,

Point estimate = sample mean =     =66.2


Population standard deviation =    = 4.1

Sample size n =400

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96   ( Using z table )


Margin of error = E = Z/2 * ( /n)

= 1.96* ( 4.1/ 400 )


= 0.40
At 95% confidence interval
is,

- E < < + E

66.2 - 0.40 <   < 66.2 + 0.40

(65.80, 66.60)


Related Solutions

A student conducts a simple random sample of students from her high school and finds that...
A student conducts a simple random sample of students from her high school and finds that 21 out of 100 students in her sample regularly walk to school. Give a point estimate for the proportion of all students at her high school who regularly walk to school. For each combination of sample size and sample proportion, find the approximate margin of error for the 95% confidence level. (Round the answers to three decimal places.) In a sample of 16 students,...
To test Ho: ? = 400 versus H1: ? > 400, a simple random sample of...
To test Ho: ? = 400 versus H1: ? > 400, a simple random sample of n = 100 is obtained. Assume the population standard deviation is 80. If the researcher decides to test this hypothesis at the ?? = .05 level of significance, compute the probability of making a Type II Error if the true population mean is 420. What is the power of the test?
In a simple random sample of 1600 young​ people, 86​% had earned a high school diploma....
In a simple random sample of 1600 young​ people, 86​% had earned a high school diploma. Complete parts a through d below. a. What is the standard error for this estimate of the percentage of all young people who earned a high school​ diploma? .0096 nothing ​(Round to four decimal places as​ needed.) b. Find the margin of​ error, using a​ 95% confidence​ level, for estimating the percentage of all young people who earned a high school diploma. nothing​% ​(Round...
The heights were recorded for a Simple Random Sample of 270 junior.  The mean of this sample...
The heights were recorded for a Simple Random Sample of 270 junior.  The mean of this sample was 66.5 inches.  The heights are known to be Normally Distributed with a population standard deviation of 5.1 inches. (You do not need a data set for this). Test the claim that the mean height of Juniors has increased from 65.7 at a 0.01 significance level. (Use MINITAB to do the hypothesis test and copy and paste the output of the hypothesis test here (0.5pts)....
The heights of a simple random sample of soccer players in a particular league are given...
The heights of a simple random sample of soccer players in a particular league are given below. Can you conclude at the 5% level of significance, that the average height of soccer players in the league sampled is over 182 cm? Assume that the heights of soccer players is normal. Show all of your work, include all necessary steps, and be complete in your answer and explanation. 193 190 185.3 193 172.7 180.3 186 188
The heights and weights of a random sample of male Senior HS basketball players are given...
The heights and weights of a random sample of male Senior HS basketball players are given in the table. Is there enough evidence that the heights and weights have a linear relationship? height/weight: (76,246), (72,207), (75,220), (74,200), (72,170), (71,175), (68,150), (74,210), (74,245), (72,200)
A simple random sample of 400 persons is taken to estimate the percentage of Republicans in...
A simple random sample of 400 persons is taken to estimate the percentage of Republicans in a large population. It turns out that 210 of the people in the sample are Republicans. True or False and explain. a. The sample percentage is 52.5%; the SE for the sample percentage is 2.5%. b. 52.5% ± 2.5% is a 75%-confidence interval for the population percentage. c. 52.5% ± 5% is a 95%-confidence interval for the sample percentage. d. 52.5% ± 5% is...
Suppose a simple random sample of athletes in the NBA heights is taken. There were 28...
Suppose a simple random sample of athletes in the NBA heights is taken. There were 28 athletes in the sample with a mean height of 78.4 inches and standard deviation of 2 inches. It has been confirmed through statistical analysis that NBA player heights follows a normal distribution. a. what parameter are we estimating? b. Explain the requirements as they relate to the problem c.What is the point estimate of the parameter? d.Input the margin of error for a 95%...
The following is a random sample of the annual salaries of high school counselors in the...
The following is a random sample of the annual salaries of high school counselors in the United States. Assuming that the distribution of salaries is approximately normal, construct a 90% confidence interval for the mean salary of high school counselors across the United States. Round to the nearest dollar. $55,250, $46,540, $42,120, $58,740, $38,010, $43,650, $65,640
2.In a high school, 16% are Freshmen, 14% are Sophomores, 38% are Juniors, and 32% are...
2.In a high school, 16% are Freshmen, 14% are Sophomores, 38% are Juniors, and 32% are Seniors. Suppose 15 students are randomly selected. Find the probability that a) 4 are Freshmen, 5 are Sophomores, and the rest are neither Freshmen nor Sophomores (in any order) b) either exactly one is Senior and all the others are not Senior (in any order) or exactly one Freshman, one Sophomore, one Junior and all the others are Seniors ( in any order) Note:...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT