In: Statistics and Probability
Suppose the amount of protein in a serving of 2 eggs follows a normal distribution with mean 12 grams and standard deviation 1 gram.
Let Y denote the amount of protein in a randomly selected serving of 2 eggs. Determine the following probabilities (enter each as a decimal, and round to 4 decimal places):
P(Y>10)
P(Y≥10)
P(Y<12)
P(Y=12)
Y denote the amount of protein in a randomly selected serving of 2 eggs
Y follows a normal distribution with mean 12 grams and standard deviation 1
P(Y>10) =1- P(Y10)
Z-score for 10 =(10-12)/1=-2/1=-2
From standard normal tables, P(Z-2) = 0.0228
P(Y10) = P(Z-1) = 0.0228
P(Y>10) = 1-P(Y10) = 1-0.0228 = 0.9772
P(Y>10) = 0.9772
P(Y 10)
As normal distribution is continuous distribution , P(Ya)=P(Y>a) ;
therefore,
P(Y10) = P(Y>10) = 0.9772
P(Y10) = 0.9772
For Normal distribution: P(Y<Mean) =P(Z<0) =0.5;
P(Y<12) = P(Y< Mean) =0.5
P(Y<12) = 0.5
For Continuous distribution P(Y=a) = 0
As normal distribution is continuous distribution , P(Y=a)=0
Therefore,
P(Y=12) = 0