In: Statistics and Probability
The amount of water consumed each day by a healthy adult follows a normal distribution with a mean of 1.32 liters. A health campaign promotes the consumption of at least 2.0 liters per day. A sample of 10 adults after the campaign shows the following consumption in liters: 1.35 1.42 1.34 1.42 1.44 1.64 1.90 1.64 1.50 1.38 At the 0.025 significance level, can we conclude that water consumption has increased? Calculate and interpret the p-value.
State the null hypothesis and the alternate hypothesis. (Round your answers to 2 decimal places.) State the decision rule for 0.025 significance level. (Round your answer to 3 decimal places.) Compute the value of the test statistic. (Round your intermediate and final answer to 3 decimal places.) At the 0.025 level, can we conclude that water consumption has increased? Estimate the p-value.
Values ( X ) | ||
1.35 | 0.0234 | |
1.42 | 0.0069 | |
1.34 | 0.0266 | |
1.42 | 0.0069 | |
1.44 | 0.004 | |
1.64 | 0.0188 | |
1.9 | 0.1576 | |
1.64 | 0.0188 | |
1.5 | 0 | |
1.38 | 0.0151 | |
Total | 15.03 | 0.2781 |
Mean
Standard deviation
Sample variance = 0.0309
To Test :-
H0 :-
H1 :-
Test Statistic :-
t = 3.2918
Test Criteria :-
Reject null hypothesis if
Result :- Reject null hypothesis
P value = P ( t > 3.2918 ) = 0.0047
reject null hypothesis if P value < level of significance
P value = 0.0047 < 0.025, hence we reject null hypothesis
Conclusion :- There is sufficient evidence to support the claim that water consumption has increased.