Question: Particles of charge +65, +48, and ?95 ?C are placed in a line (Figure 1)...

Question: Particles of charge +65, +48, and ?95 ?C are placed in a line (Figure 1) . The center one is L = 35cm from each of the others.

Part A: Calculate the net force on the left charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left.

Part B: Calculate the net force on the center charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left.

Part C: Calculate the net force on the right charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left.

Expert Solution

B. the MIDDLE charge experience repulsive force F due to the first and attractive force F due to the right charge. so the net foce is F = F₁- F₂ = 1/4₀ [ Q₁Q₂ - Q₂Q₃] / d ²

F = 9x10⁹ [ 65x48 - 48x95] x10^-12 / 35² = 10.579x10^-3 N

A.. the left charge experience repulsive force F₁ due to the middle and attractive force F₂ due to the right charge. so the net force F = 1 / ₀ [ Q₁Q₂ - Q₂Q₃] / d

F = 9x10 [ 65x48/35² - 65x95/70² ]x10^-12 = 11.518x10^-3 N

C. force experienced by the third charge is attractive force F₁by both first and F₂ bymiddle

charge.so the net force F = F₁ + F₂ = 1/4₀ [65x95 / 70² + 48x95/35² ] 10 ^-12

= - 44.84x10^-12 N

genius_generous answered 5 months ago

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