Two point charges are placed on the x axis. (Figure 1)The first charge, q1 = 8.00...

Two point charges are placed on the x axis. (Figure 1)The first charge, q1 = 8.00 nC , is placed a distance 16.0 m from the origin along the positive x axis; the second charge, q2 = 6.00 nC , is placed a distance 9.00 m from the origin along the negative x axis.

An unknown additional charge q3 is now placed at point B, located at coordinates (0 m, 15.0 m ). Find the magnitude and sign of q3 needed to make the total electric field at point A equal to zero.

Two charges, labeled q 1 and q 2, are shown on the xy-plane. Point O is at the origin. Charge q 1 lies on the positive x-axis at distance 16 meters from the origin. Charge q 2 lies on the negative x-axis at distance 9 meters from the origin. Points A and B are marked on the positive y-axis at distances 12 meters and 15 meters from the origin, respectively.

Expert Solution

Position vector from ql, F-16 m,12 m>(-16m)+(12m-20m Position vector from q2, <-16m, 12m >=<-0.8,0.6% F1-20m 15m Position ve E+E2+E-0 r2 Now, lets plug all values, 20m) (15m) 0.18「+0.24ん+10q3r3:0 0.18<-0.8,0.6>+0.24<0.6,0.8>+109q,<0,-1>=0 <-0.144, 0.3-10q0 0.3 3-109 10 q3-0.3x10%C_ + 0.3 nC A ns.

genius_generous answered 2 years ago

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