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A horizontal rectangular piston contains 1.85 mol of a polyatomic ideal gas at a pressure of...

A horizontal rectangular piston contains 1.85 mol of a polyatomic ideal gas at a pressure of 1.013x10^5 Pa and a temperature of 322.5 C. The gas within the piston is cooled to 264.0 C. (a) If the piston undergoes an isovolumetric process, what is the change in entropy of the gas? J/K (b) If the piston undergoes an isobaric process inside the chamber, what is the change in entropy of the gas? J/K

Solutions

Expert Solution

a)   change in entropy of the gas = nCv ln (T2 / T1)

                                                    =   1.85 * 3R * ln(322.5/264.0)

                                                     =   1.85 * 3 * 8.314 * ln(322.5/264.0)

                                                     =   9.235 J/K

b)   change in entropy of the gas = nCp ln (T2 / T1)

                                                    =   1.85 * 4R * ln(322.5/264.0)

                                                     =   1.85 * 4 * 8.314 * ln(322.5/264.0)

                                                     =   12.314 J/K

genius_generous answered 2 years ago
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