Question

Consider this code: "int v = 20; --v; System.out.println(v++);". What value is printed, what value is v left with?

20 is printed, v ends up with 19
19 is printed, v ends up with 20
20 is printed, v ends up with 20
19 is printed, v ends up with 19
cannot determine what is printed, v ends up with 20

Answer 1

*************Summary***************

The answer for above question is given below and also the explanation.....

I have also provided a program with output for reference...showing the correct answer as output..

I hope it works for you :) !!!!!!!!!!!!!!!!!!!

**************Answer****************

The answer for above question is 19 is printed, v ends up with 20 ....

************Explanation**************

1. int v=20;

v is intialized to 20 so value of v=20

2. --v;

as the - - signs are before v...so it pre decrement operation...that means the value is decremented first and then rest of the statement is executed...so the value of v will be 19...v=19

3. System.out.println(v++);

as the ++ signs are after variable v..so it is post increment operation......that means first the statement is executed with current value of v ....and then the it increments the value of v....

1. so when executing system.out.println(v++) ..it uses the current value of v i.e v=19..so it prints 19 ........

2. And when statement has done executing ..then it increments the value of v ...so the latest value of v becomes 20.....

So from 1 and 2

19 is printed because it executes statement first with current value of v

and v ends up with 20 because it increments value of v after execution of that statement

*****************Program*******************

import java.util.Scanner;

public class Main
{
  public static void main(String args[])
  { 
    int v=20;    //inutializing v to 20
    
    --v;    //pre decrementing value of v...v will be 19
    
    System.out.println(v++);    
    //as there is post increment operator (++ operator after variable v).
    //..so it will print current value of v i.e. 19 using the system.out.println
    //and then after the printing of value of v
    //it will increment value of v ..so value of will be 20 after execution 
      
    //to check the value with which v ends up
    System.out.println("V ends up to with "+v);
  }
}

*****************Output*********************