Question

Find the output for the following statements.

• System.out.println(3%2+1+(3/2));

• char ch = 69;
  System.out.println(ch);

• int x = 30;

int y = 4;

double z = x/y;

System.out.println(z);

Answer 1

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Note : check attached image for output .

Answer :

       1. System.out.println(3%2+1+(3/2)); //output will 3 how ?

        how ? : -

          first it will solve bracket so 3/2 = 1 both operand integer so 3/2 will be 1 now equation is

         System.out.println(3%2+1+1);

         in Java operator precedence + come after % in precedence

           System.out.println(1+1+1); //3%2=1

            System.out.println(3); //output

         

        2. char ch = 69; //69 ascii value of 'E'
             System.out.println(ch); //it will print E on console

         3. int x = 30;
            int y = 4;
            double z = x/y; z=30/4

       by mathematic the result should be 7.5 but output will be 7.

       why both operand x and y are integer type so result will also integer type . to get double

        we should type cast the result z= (double)x/y = 7.5
        System.out.println(z); //it will print 7 without type casting

Output :

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