In: Statistics and Probability
Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of
0.100.10
to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds).
Household Paper Plastic
1 6.05 2.73
2 5.86 3.91
3 6.98 2.65
4 16.39 9.70
5 12.73 14.83
6 7.98 6.09
7 15.09 9.11
8 8.82 11.89
9 9.45 3.02
10 11.08 12.47
11 11.42 12.81
12 6.16 5.88
13 13.61 8.95
14 6.96 7.60
15 9.19 3.74
16 20.12 18.35
17 16.08 14.36
18 2.80 5.92
19 6.83 3.57
20 12.32 11.17
21 9.83 6.26
22 6.67 6.09
23 7.72 3.86
24 12.43 8.57
25 9.41 3.36
26 2.41 1.13
27 11.36 10.25
28 6.44 8.40
29 7.57 5.92
30 9.55 9.20
In this example,
mu Subscript dμd
is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesistest?
A.
Upper H 0H0:
mu Subscript dμdnot equals≠0
Upper H 1H1:
mu Subscript dμdequals=0
B.
Upper H 0H0:
mu Subscript dμdequals=0
Upper H 1H1:
mu Subscript dμdless than<0
C.
Upper H 0H0:
mu Subscript dμdequals=0
Upper H 1H1:
mu Subscript dμdnot equals≠0
D.
Upper H 0H0:
mu Subscript dμdnot equals≠0
Upper H 1H1:
mu Subscript dμdgreater than>0
Identify the test statistic.
tequals=nothing
(Round to two decimal places as needed.)
Identify the P-value.
P-valueequals=nothing
(Round to three decimal places as needed.)
What is the conclusion based on the hypothesis test?
Since the P-value is
▼
less
greater
than the significance level,
▼
reject
fail to reject
the null hypothesis. There
▼
is
is not
sufficient evidence to support the claim that there is a difference between the weights of discarded paper and discarded plastic