In: Statistics and Probability
A report describes results of a survey of nearly 2,000 college faculty. The report indicates the following.
Consider the chance experiment that selects one of the study participants at random and define the following events.
(a)
Two of the percentages given in the problem specify unconditional probabilities, and the other two percentages specify conditional probabilities. Which are conditional probabilities?
69.5% said that they did not use Twitter.30.5% reported that they use TwitterOf those who use Twitter, 26.5% said that they sometimes use Twitter as a learning tool in the classroom.Of those who use Twitter, 39.8% said they sometimes use Twitter to communicate with students.
(b)
Use the given information to determine the following probabilities. (Round your answers to three decimal places.)
(i)
P(T )
(ii)
P(T C)
(iii)
P(C|T )
(iv)
P(L|T )
(c)
Complete the following hypothetical 1,000 table using the given probabilities. (Round your answers to the nearest integer.)
Uses Twitter (T) | Does Not Use Twitter (not T) | Total | |
---|---|---|---|
Uses Twitter to Communicate with Students (C) | |||
Does Not Use Twitter to Communicate with Students (not C) | |||
Total | 1,000 |
Use the information in the table to calculate
P(C),
the probability that the selected study participant sometimes uses Twitter to communicate with students.
(d)
Complete the following hypothetical 1,000 table using the given probabilities. (Round your answers to the nearest integer.)
Uses Twitter (T) | Does Not Use Twitter (not T) | Total | |
---|---|---|---|
Uses Twitter as a Learning Tool in Classroom (L) | |||
Does Not Use Twitter as a Learning Tool in Classroom (not L) | |||
Total | 1,000 |
Use the information in the table to calculate
P(L),
the probability that the selected study participant sometimes uses Twitter as a learning tool in the classroom.
ANSWER a:
The two conditional probabilities are-
As, the students have to first use Twitter in order to communicate or use it as a learning tool.
and, The two unconditional probabilities are-
ANSWER b:
Given,
i. P(T)= 0.305
ii. P(T C) = P(C|T) P(T) = 0.3980.305 = 0.121 ( upto 3 decimal places)
iii. P(C|T) = 0.398 ( from the question)
iv. P(L|T)= 0.265 (from the question)
ANSWER c:
By taking the above probabilities the hypothetical 1000 table is given as-
Uses Twitter (T) |
Does not use Twitter (not T) |
Total |
|
Uses Twitter to Communicate with Students (C) |
121 |
0 |
121 |
Does Not Use Twitter to Communicate with Students (not C) |
184 |
695 |
879 |
Total |
305 |
695 |
1000 |
Therefore,
P(C),the probability that the selected study participant sometimes uses Twitter to
communicate with students= 121/1000=0.121
ANSWER d:
By taking the above probabilities the hypothetical 1000 table is given as-
Uses Twitter(T) |
Does not use Twitter(not T) |
Total |
|
Uses Twitter as Learning Tool in classroom(L) |
81 |
00 |
81 |
Does not use Twitter as a Learning tool in classroom(not L) |
224 |
695 |
919 |
Total |
305 |
695 |
1000 |
Therefore,
P(L),the probability that the selected study participant sometimes uses Twitter
as a learning tool in the classroom= 81/1000=0.081