In: Advanced Math
Find f(1), f(2), f(3) and f(4) if f(n) is defined recursively by
f(0)=4f(0)=4 and for n=0,1,2,…n=0,1,2,… by:
(a) f(n+1)=−2f(n)
f(1)=
f(2)=
f(3)=
f(4)=
(b) f(n+1)=4f(n)+5
f(1)=
f(2)=
f(3)=
f(4)=
(b) f(n+1)=f(n)2−4f(n)−2
f(1)=
f(2)=
f(3)=
f(4)=