Question

In this lab, I want you to take in a numeric grade as an integer and then print a letter grade per the table below:

90 or above is an A

80 or above is a B

70 or above is a C

60 or above is a D

Below a 60 is an F

You must use a branching statement that prints the appropriate letter grade based on the user input2. Please comment your code

Answer 1

Code is as follows as per the problem statement:

#include <iostream>

using namespace std;

int main() {
    int grade=0;
    cout<<"Enter the grade(number) : "; //marks secured is given as an input to the program
    cin>>grade;
    if (grade>=90)                      //condition check for giving A grade
        cout<<"\n Grade Secured is A";
    else if(grade>=80)                  //condition check for giving B grade
        cout<<"\n Grade Secured is B";
    else if(grade>=70)                  //condition check for giving C grade
        cout<<"\n Grade Secured is C";
    else if(grade>=60)                  //condition check for giving D grade
        cout<<"\n Grade Secured is D";
    else
        cout<<"\n Grade Secured is F";  //if the above conditions fail then give grade as F
    return 0;
}

Dear Student, As you have not mentioned the programmming language to be used for the problem statement, I have given the answer in C++ as it is widely acceptable.

Explanation:

• First we give the marks secured by a student as an input to the program as the standard input.
• We have used the variable "grade" for the purpose of storing the input marks given.
• Then we check the condition as per the given rules via if else statements (conditional branching)
• The correct alphabetical grade is printed on the output screen according to the conditions.

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