Question

in java please!!!

suppose there is a text file named TextFile.txt with some data in the root directory (e.g. C:\ or \) of your computer. In JAVA, write code that (i) opens the file in read mode; (ii) displays the file content on the monitor screen/console; (iii) uses exception handling mechanism with try, catch, and finally blocks; and (iv) safely closes the file. Writing the main() method is optional.

Answer 1

Java Code:-

import java.io.*;
public static void readFile {

    String fileName ="C:\\tesstfile.doc";
  
    BufferedReader reader = null;
    try {
        reader = new BufferedReader(new FileReader(new File(fileName)));
        String line =null;
        while ((line = reader.readLine())!=null){
            System.out.println(line);
        }
    } catch (FileNotFoundException e) {

    } catch (IOException e) {

    } finally {
        if(reader!=null) {
            try {
                reader.close(); // close the file surrounded by try catch block
            } catch (IOException e) {

            }
        }
    }

}

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Note: Could you please consider my effort on this work and give me a UPVOTE. Thank you :)