Question

in c++ language

This assignment is to give you practice using structs and sorting.

In competitive diving, each diver makes dives of varying degrees of difficulty. Nine judges score each dive from 0 through 10 in steps of 0.5. The difficulty is a floating-point value between 1.0 and 3.0 that represents how complex the dive is to perform. The total score is obtained by discarding the lowest and highest of the judges’ scores, adding the remaining scores, and then multiplying that total by the degree of difficulty. Write a program to score each of the dives, using the following input and output specifications, and determine the winner of the competition.

Input:

Create the file m7divers.txt using the data given at the end.

The first line contains an integer for the number of divers in the competition and subsequent lines contain:
Diver’s name (10 characters max, no blanks included), difficulty (double), and judges’ ratings (nine doubles). There is one line of data for each diver.

Example file: (This is not the data to use)

Anne	2.0	8.0	8.5	8.5	8.5	9.0	9.0	9.0	9.5	9.5	124.0
Sarah	1.6	7.0	7.5	8.0	8.0	8.0	8.5	8.5	8.5	9.0	91.2

Output:

The name and difficulty, followed by the scores sorted into increasing order, in tabular form with appropriate headings along with the earned total points for that dive.

Example for sample data above

NAME	DIFF	SORTED SCORES									POINTS
Anne	2.0	8.0	8.5	8.5	8.5	9.0	9.0	9.0	9.5	9.5	124.0
Sarah	1.6	7.0	7.5	8.0	8.0	8.0	8.5	8.5	8.5	9.0	91.2

At the end of the table, print out the name of the winner of the competition (the person with the highest points) and his/her final score.

Hint: Use functions to modularize your program.

Use this data for your input file. download the data from the attachment.

NAME	DIFF	SORTED SCORES
Anne	2.0	8.0	8.5	8.5	8.5	9.0	9.0	9.0	9.5	9.5
Sarah	1.6	7.0	7.5	8.0	8.0	8.0	8.5	8.5	8.5	9.0
Deborah	2.3	9.0	9.0	9.5	10.0	10.0	9.5	9.5	9.5	9.5
Kathryn	2.4	9.0	9.0	9.0	9.5	9.5	9.5	9.0	8.0	8.5
Martha	2.7	9.0	9.0	9.5	9.5	9.0	8.5	8.5	8.5	8.5
Elizabeth	2.9	8.0	8.0	7.5	8.5	8.5	8.0	8.0	7.5	8.5
Tina	2.5	8.5	8.5	8.5	8.5	8.5	8.5	8.5	8.5	8.5

Answer 1

DATA FILE: m7divers.txt

Create the data file as text file named m7divers.txt with following data and store it in the same folder where your C++ program is stored. The individual data items should be separated by tabs. Make sure that no blank line is present after the line with last data line.

7

Anne             2.0       8.0       8.5       8.5       8.5       9.0       9.0       9.0       9.5       9.5

Sarah             1.6       7.0       7.5       8.0       8.0       8.0       8.5       8.5       8.5       9.0

Deborah       2.3       9.0       9.0       9.5       10.0    10.0    9.5       9.5       9.5       9.5

Kathryn        2.4       9.0       9.0       9.0       9.5       9.5       9.5       9.0       8.0       8.5

Martha          2.7       9.0       9.0       9.5       9.5       9.0       8.5       8.5       8.5       8.5

Elizabeth      2.9       8.0       8.0       7.5       8.5       8.5       8.0       8.0       7.5       8.5

Tina             2.5       8.5       8.5       8.5       8.5       8.5       8.5       8.5       8.5       8.5

//PROGRAM

//////////////////////////////////////////////////////

// CALCULATING SCORES OF SWIMMERS                   //

//////////////////////////////////////////////////////

//include header files

#include<iostream>

#include<iomanip>

#include<fstream>

//maxmimum size of divers

//for declaring the size of structures

#define MAX 10

//include std name space

using namespace std;

//swap two variables

//used by the sort function

//parameters: two floating-point numbers

//output: contents get swapped

//side effects: None

void swap(float a, float b)

{

    int temp = a;

    a = b;

    b = temp;

}

//function to implement bubble sort

//parameters: floating-point array of numbers and its size

//output: sorted array

//side effects: None

void sort(float arr[], int n)

{

    int i, j;

    for (i = 0; i < n-1; i++)

        for (j = 0; j < n-i-1; j++)

            if (arr[j] > arr[j+1])

                swap(arr[j], arr[j+1]);

}

//main function

int main(void)

{

    fstream indata; //declaring input file stream

    struct //stucture to hold details of divers

    {

        string name; // holds name

        float diff; // holds diificulty level

        float score[9]; //holds 9 scores

        float total; //holds total score

    }diver[MAX]; //array of divers

    int i,j, divers, winner, maxpoint;

    //opening the input file containing data

    indata.open("m7divers.txt",ios::in);

    //check if data file is created or not

    if(!indata)

    {

        cout<<"Data File missing."

        <<"Create a text file named m7divers.txt"

        <<" with the given data";

        return 0;

    }

    //set precision and fixed point flag

    cout.precision(1);

    cout<<fixed;

    //get number of divers from file

    indata>>divers;

    //initialized index of diver

    i=0;

    //read data of divers from file

    while(!indata.eof())

    {   indata>>diver[i].name>>diver[i].diff;

        for(int j=0;j<9; j++)

            indata>>diver[i].score[j];

        i++;

   }

    //sort diver scores

    for(int i=0;i<divers; i++)

        sort(diver[i].score,9);

    //initialize winner and

    //maximum point of the winner

    winner=0;

    maxpoint=0;

    //calculate totals of divers

    //also finds winner

    for(int i=0;i<divers; i++)

    {

        diver[i].total=0;

        for(int j=1;j<8; j++)

            diver[i].total += diver[i].score[j];

        diver[i].total *= diver[i].diff;

        if(maxpoint<diver[i].total)

        {   maxpoint=diver[i].total;

            winner=i;

        }

    }

    //display the table headings

    cout<<endl<<"-------------------------------------------------------------------";

    cout<<endl<<"      NAME DIFF S1   S2   S3   S4   S5   S6   S7   S8   s9   TOT";

    cout<<endl<<"-------------------------------------------------------------------";

    //display details of each diver

    for(i=0;i<divers;i++)

    {   cout<<endl<<setw(10)<<diver[i].name<<" "<<setw(4)<<diver[i].diff<<" ";

        for(int j=0;j<9; j++)

            cout<<" "<<setw(4)<<diver[i].score[j];

        cout<<" "<<setw(6)<<diver[i].total;

    }

    //display winner as footer of the table

    cout<<endl<<"-------------------------------------------------------------------";

    cout<<endl<<"Winner is "<<diver[winner].name<<" with a total score of "<< diver[winner].total;

    cout<<endl<<"-------------------------------------------------------------------";

    return 0;

}

SCREENSHOT OF PROGRAM

OUTPUT OF SUCCESSFUL RUN IN CODE::BLOCK

-------------------------------------------------------------------

      NAME DIFF S1   S2   S3   S4   S5   S6   S7   S8   s9   TOT

-------------------------------------------------------------------

      Anne 2.0   8.0 8.5 8.5 8.5 9.0 9.0 9.0 9.5 9.5 124.0

     Sarah 1.6   7.0 7.5 8.0 8.0 8.0 8.5 8.5 8.5 9.0   91.2

   Deborah 2.3   9.0 9.0 9.5 10.0 10.0 9.5 9.5 9.5 9.5 154.1

   Kathryn 2.4   9.0 9.0 9.0 9.5 9.5 9.5 9.0 8.0 8.5 152.4

    Martha 2.7   9.0 9.0 9.5 9.5 9.0 8.5 8.5 8.5 8.5 168.8

Elizabeth 2.9   8.0 8.0 7.5 8.5 8.5 8.0 8.0 7.5 8.5 162.4

      Tina 2.5   8.5 8.5 8.5 8.5 8.5 8.5 8.5 8.5 8.5 148.8

-------------------------------------------------------------------

Winner is Martha with a total score of 168.8

-------------------------------------------------------------------

SCREENSHOT OF SUCCESSFUL RUN IN CODE::BLOCK