In: Operations Management
Q1: A firm produces 3 products. These products are processed on 3 different machines. The time required to manufacture 1 unit of each of the 3 products and the daily capacity of the 3 machines are given in the table below:
| 
 Machine  | 
 Time per unit (mins)  | 
 Machine capacity (mins/day)  | 
||
| 
 Product 1  | 
 Product 2  | 
 Product 3  | 
||
| 
 M1  | 
 2  | 
 3  | 
 2  | 
 440  | 
| 
 M2  | 
 4  | 
 -  | 
 3  | 
 470  | 
| 
 M3  | 
 2  | 
 5  | 
 -  | 
 430  | 
It is required to determine the daily number of units to be manufactured for each product. The profit per unit for product 1, 2, and 3 is $4, $3, and $6 respectively. It is assumed that all the amounts produced are consumed in the market. Formulate the mathematical model for the problem.
Solution:
Since only the formulation is required, we will not solve the formulated LPP.
Let no. of product 1 be x, product 2 be y and product 3 be z
Total profit = 4*x + 3*y + 6*z
We have to maximize this profit
Hence, we get the objective function as:
Maximize Total Profit P = 4x + 3y + 6z
Total time required in Machine M1 = 2x + 3y + 2z
Total time available = 440 mins/ day
Hence, we get constraint as 2x + 3y + 2z <= 440
Similalrly for machine M2, 4x + 0y + 3z <= 470
For machine M3, 2x + 5y + 0z <= 430
Hence, we get formulation of mathematical model as
Maximize Total Profit P = 4x + 3y + 6z
Subject to Constraints:
2x + 3y + 2z <= 440
4x + 0y + 3z <= 470
2x + 5y + 0z <= 430
x, y, z >= 0..................Non-negativity constraint since no. of product scannot be negative
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