Question

Write a program that will search through an array and check to see if the first number in the array occurs more than once. If the first number occurs more than once, return true. Otherwise, return false. If the array is empty, return false?

You will need to use a variable, loop, and if statement.

Answer 1

In c++ it can be written as:-

#include<iostream>

using namespace std;

main(){
   cout<<"Please enter the array elements\n"; //prompting the user to enter the array elements
   int a[5]; //declaring array of size 5
   for(int i=0;i<5;i++)
   {
       cin>>a[i]; //storing the entered values in the array
   }
  
   int firstnum,count=0; // variables for storing first element and count of first element, respectively.
  
   firstnum=a[0]; //assigning the first element
  
   for(int i=0;i<5;i++)
   {
       if(firstnum==a[i])
       count=count+1; //increasing the value of count if the variable is equal to the element in the array
   }
  
   if(count>=2) //if the count is greater than 2 then print true else false   
   cout<<"TRUE";
   else
   cout<<"FALSE";
}

The Screenshot of code and output are given below:-

Output when the first element is non repeating:-

Output when the first element is repeating:-