Question

Please make a C program named:

rotate.c

This code will contain a single function (and the include directive to your header file) to perform the rotation operation using the two integer operands passed to this function. The first integer operand is the number to be rotated. The second integer operand is the number of bit positions that the first operand must be rotated by.

EXAMPLE:

Enter a 32-bit number (>= 1 and <= 4294967295, inclusively): 1

Enter the number of positions to rotate-right the input (between 0 and 31, inclusively): 1

1 rotated by 1 position gives: 2147483648

Answer 1

The following is the code for above question.

#include <stdio.h>
#define BITS 32
int rotate(int number,unsigned int bit_positions)
{ //here we know, in number>>bit_positions the first bit_positions bits are 0. BITS-bit_positions gives the last digits and hence bitwise between number>>bit_positions) and number<<(BITS-bit_positions) will rotate the number right by bit_positions digits 
    return (number>>bit_positions)|(number<<(BITS-bit_positions));
}
int main()
{
    int number,bit_positions;
    printf("Enter a 32-bit number (>= 1 and <= 4294967295, inclusively): ");
    scanf("%d",&number);
    printf("\nEnter the number of positions to rotate-right the input (between 0 and 31, inclusively): ");
    scanf("%d",&bit_positions);
    printf("\n%d rotated by %d position gives: %d",number,bit_positions,rotate(number,bit_positions));
    return 0;
}

I am also attaching the output for your reference.

Output:

Enter a 32-bit number (>= 1 and <= 4294967295, inclusively): 1

Enter the number of positions to rotate-right the input (between 0 and 31, inclusively): 1

1 rotated by 1 position gives: -2147483648

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