5. A wireless LAN using direct sequence spread spectrum (DSSS) needs 224 Mbps for sending data...

5. A wireless LAN using direct sequence spread spectrum (DSSS) needs 224 Mbps for sending data that was originally sent at 32 Mbps. How many bits are in the chip code? please show your work....

Expert Solution

DSSS defines IEEE 802.11a,b,g and n. Among them a and g has 54Mbps and n has 600Mbps. Since, orignal data is transmitted at 32 Mbps it can be either IEEE802.11 a or IEEE802.11 g.

IEEE 802.11a uses Orthogonal Frequency Division Multiplexing (OFDM). DSSS WLAN systems uses binary phase-shift keying (BPSK) and quadrature phase-shift keying (QPSK) modulation techniques. It us required to develop higher data rate DSSS WLAN systems, it is required to replace BPSK and QPSK schemes with more complex modulation techniques. Those are M-ary orthogonal keying (MOK), complementary code keying (CCK), cyclic-code shift keying (CCSK), pulse-position modulation (PPM), quadrature amplitude modulation (QAM), orthogonal code division multiplexing (OCDM), and orthogonal frequency division multiplexing (OFDM).

The given data tells 224 Mbps sending data that was originally sent at 32 Mbps. If we divide 224/ 32 we get 7 (bits). However, spreading factor (SF) or processing gain can be calucated using SF= chiprate/ symbol rate. Here SF is always in 2^n. So, we have 2^3 =8. ( so chip code is 8 ).

venereology answered 1 month ago

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