Question

User is asked to enter a series of numbers. That input will stop when user enters -9999. Find a maximum number from that series and a minimum number from that series. Output the location of Maximum number and minimum number. 

Write a C++ program that asks the user to repeatedly input positive numbers until   -1 is pressed. Your program should print the second largest number and the count of even and odd numbers. 

Write a C++ program that asks the user to enter a positive number N, and print the following pattern. The pattern is shown for N = 5.

12345

23451

34521

45321

54321

Write a program that takes a set of N integers and count the frequency of ODD digits appeared in these N integers.

Sample Input:

How Many Numbers you want to input: 3

Number 0: 7809

Number 1: 1127

Number 2: 8381

Output: 

    Frequency of appeared ODD digits: 7

 The digits 7809. 5127. 8381. So the count of these ODD digits is 7.

Answer 1

1)

#include<iostream>
using namespace std;

int main()
{
    int x,min=999999,max=-99999;
    int minpos=0,maxpos=0,count=0;
    cin>>x;
    while(x!=-9999)
    {
        count++;
        if(x > max)
        {
            max = x;
            maxpos = count;
        }
        if( x < min)
        {
            min = x;
            minpos = count;
        }
        cin>>x;
    }
  
    cout<<"Maximum number is : "<<max<<" And its location is : "<<maxpos<<endl;
    cout<<"Minimum number is : "<<min<<" And its location is : "<<minpos<<endl;
  
    return 0;
}

Input:

15
13
33
99
55
-9999

Output :

Maximum number is : 99 And its location is : 4
Minimum number is : 13 And its location is : 2

2)

#include<iostream>
using namespace std;

int main()
{
   int x,max2=-999999,max=-999999;
   int numodd=0,numeven=0;
   cin>>x;
   while(x!=-1)
   {
       if(x%2 == 0)
           numeven++;
       else
           numodd++;

       if(x > max)
       {
           max = x;
       }
       if( x < max && x > max2)
       {
           max2 = x;
       }
       cin>>x;
   }
  
   cout<<"Second largest number is : "<<max2<<endl;
   cout<<"Count of odd numbers is : "<<numodd<<" And count of even numbers is : "<<numeven<<endl;
  
   return 0;
}

Input :

15
13
33
99
55
-1

Output :
Second largest number is : 55
Count of odd numbers is : 5 And count of even numbers is : 0

3)

#include<iostream>
using namespace std;

int main()
{
   int N,i,j,x;
   cout<<"Enter a positive number (N) : ";
   cin>>N;
  
   for(x=1;x<=N;x++)
   {
       for(i=x;i<=N;i++)
       {
           cout<<i;
       }
       j=x-1;
       while(j>0)
       {
           cout<<j;
           j--;
       }
       cout<<endl;
   }
  
   return 0;
}

Input:

Enter a positive number (N) : 7

Output:

1234567
2345671
3456721
4567321
5674321
6754321
7654321

4)

#include<iostream>
using namespace std;

int main()
{
   int N,i,num[50],odddigits=0;
   cout<<"How many numbers you want to input : ";
   cin>>N;
  
   for(i=0;i<N;i++)
   {
       cout<<"Number"<<i<<": ";
       cin>>num[i];
      
   }
  
   for(int i=0;i<N;i++)
   {
       int x=num[i];
       while(x)
       {
           if((x%10)%2 != 0)
               odddigits++;
           x /= 10;
       }
   }
   cout<<"Frequency of appeared ODD digits : "<<odddigits<<endl;
  
  
   return 0;
}

Input :
How many numbers you want to input : 3
Number 0: 7809
Number 1: 1127
Number 2: 8381

Output:

Frequency of appeared ODD digits : 7