Question

II. Application 1 and 2 run concurrently. Whenever a timeout interrupt occurs, the kernel switches control between the applications. Show the order of instruction execution, assuming application 1 is currently running. (42 pts)

Application 1	Application 2
... instruction i (timeout interrupt) instruction i+1 ... instruction k (timeout interrupt) instruction k+1 ...	instruction 0 ... instruction j (timeout interrupt) instruction j+1 ...

1. _______

2. _______

3. _______

4. _______

5. _______

6. _______

Answer 1

Required Sequence of Execution:

1) application 1 started and continues execution from instruction 0 to instruction i

instruction i (application 1)

-------------------timeout interruption --------------------------(switching control--application 1 paused)--------------------------

2) instruction 0 (application 2 started)

...........instructions of applications 2 will continue from instruction 0 to instruction j

instruction j (application 2)

-------------------timeout interruption --------------------------(switching control--application 2 paused)--------------------------

3) instruction i+1 (application 1 begins)

...........instructions of applications 1 will continue from instruction i+1 to instruction k

instruction k (application 1)

-------------------timeout interruption --------------------------(switching control--application 1 paused)--------------------------

4) instruction j+1 (application 2 begins)

........application 2 will continues its execution until it completes all its instructions and then it gets terminated

.......application 2 terminated

5) instruction k+1 (application 1 begins)

........application 1 will continues its execution until it completes all its instructions and then it gets terminated

........application 1 terminated

Note: since the number of items required in the question is mentioned as 6 number of items but as the total number of executions is total 5 in number hence their order is as mentioned above.