Question

In: Math

Suppose µX and µY are the true mean stopping distances when starting at 50 mph for...

Suppose µX and µY are the true mean stopping distances when starting at 50 mph for cars of a
certain type equipped with two different braking systems (System X vs. System Y). The
following data was obtained for each braking system:

System X    System Y
nx = 8           ny = 8
x = 85.7 ft    y = 96.3 ft
sx = 4.36 ft sy = 5.18 ft
Consider the following hypotheses:
Ho: µX - µY = -5
Ha: µX - µY < -5
As indicated by the alternative hypothesis, it is believed that cars equipped with System X
are able to stop over a shorter distance than cars equipped with System Y. Does the data
support this hypothesis at the 1% level?

Solutions

Expert Solution

Ho: µX - µY = -5
Ha: µX - µY < -5

Firstly to conduct this we need to check the assumption of homogeneity of variances

So for that

F= sx^2/sy^2

F= (4.36)^2/(5.18)^2

F= 0.708

P value= 0.6699> 0.05 level of significance therefore not significant . Hence variances are equal.

Now

We can proceed with indepednent t test

where sp is pooled stanadrd deviation

Pooled Standard Deviation: 4.7876

d.f =8+8-2= 14

The P-Value is .017308. The result is not significant because p > .01.

Decsion: Fail to reject null hypothesis H0.

Conclusion: We don't have sufficient evidence to conclude that  cars equipped with System X
are able to stop over a shorter distance than cars equipped with System Y at 0.01 level of significance.


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