In: Statistics and Probability
The amount of fill (weight of contents) put into a glass jar of spaghetti sauce is normally distributed with mean μ = 843 grams and standard deviation of σ = 8 grams.
(a) Describe the distribution of x, the amount of fill per jar.
1) skewed right
2) normal
3) skewed left
4) chi-square
_
(b) Find the probability that one jar selected at random contains
between 835 and 865 grams. (Give your answer correct to four
decimal places.)
_
(c) Describe the distribution of x, the mean weight for a
sample of 20 such jars of sauce.
1) skewed right
2) normal
3) skewed left
4) chi-square
_
(d) Find the mean of the x distribution. (Give your answer
correct to the nearest whole number.)
(ii) Find the standard error of the x distribution. (Give
your answer correct to two decimal places.)
(e) Find the probability that a random sample of 20 jars has a mean
weight between 835 and 865 grams. (Give your answer correct to four
decimal places.)
olution :
Given that,
mean = = 843
standard deviation = = 8
A ) The distribution of x, the amount of fill per jar.
Option normal is correct.
B ) P ( 835 < x < 865 )
P ( 835 - 843 / 8) < ( x - / ) < ( 865 - 843 / 8)
P ( - 8 / 8 < z < 22/ 8 )
P (- 1 < z <2.75 )
P (z < 2.75 ) - p ( z < - 1 )
Using z table
= 0.9970 - 0.1587
= 0.8383
Probability = 0.8383
C ) The distribution of x, the mean weight for a sample of 20 such jars of sauce.
Option normal is correct.
D ) n = 20
The mean of the x distribution.
= 843
The standard error of the x distribution.
= ( /n) = (8 / 20 ) = 1.79
E ) P ( 835 < < 865 )
P ( 835 - 843 / 1.79) < ( - / ) < ( 865 - 843 / 1.79)
P ( - 8 / 1.79 < z < 22/ 1.79 )
P (- 4.47 < z < 12.29)
P (z < 12.29 ) - p ( z < - 4.47 )
Using z table
= 1 - 0
= 1.0000
Probability = 1.0000