Question

In: Statistics and Probability

Assume that daily TV viewing is normally distributed and has a mean of 8 hours per...

Assume that daily TV viewing is normally distributed and has a mean of 8 hours per household with a standard deviation of 2 hours. Find the following probabilities:

Probability that a randomly selected household views TV more than 10 hours a day, i.e. P( x > 10)
Probability that a randomly selected household views TV more more than 11 hours a day, i.e. P(x > 11)
Probability that a randomly selected household views TV less than 3 hours a day, i.e. P(x < 3)
Probability that a randomly selected household views TV between 10 and 12 hours a day, i.e. P( 10 < x < 12)

Solutions

Expert Solution

Let "X" be household views TV more than 10 hours a day.

Refer Z-table to find the probability or use excel formula "=NORM.S.DIST(1, TRUE)" to find the probability.

---------------------------------------------------------------------------------------------------------------

Refer Z-table to find the probability or use excel formula "=NORM.S.DIST(1.5, TRUE)" to find the probability.

---------------------------------------------------------------------------------------------------------------

Refer Z-table to find the probability or use excel formula "=NORM.S.DIST(-2.5, TRUE)" to find the probability.

---------------------------------------------------------------------------------------------------------------

Refer Z-table to find the probability or use excel formula "=NORM.S.DIST(2, TRUE)" & "=NORM.S.DIST(1, TRUE)" to find the probability.

orchestra answered 1 year ago

Next > < Previous

Related Solutions

Assume that daily TV viewing is normally distributed and has a mean of 8 hours per...

Assume that daily TV viewing is normally distributed and has a mean of 8 hours per household with a standard deviation of 2 hours. Find the following probabilities: Probability that a randomly selected household views TV more than 10 hours a day, i.e. P( x > 10) Probability that a randomly selected household views TV more more than 11 hours a day, i.e. P(x > 11) Probability that a randomly selected household views TV less than 3 hours a day,...

Suppose that the mean daily viewing time of television is 8.35 hours.

Suppose that the mean daily viewing time of television is 8.35 hours. Use a normal probability distribution with a standard deviation of 2.5 hours to answer the following questions about daily television viewing per household (a) What is the probability that a household views television between 5 and 11 hours a day? (Round your answer to four decimal places.) Incorrect: Your answer is incorrect. (b) How many hours of television viewing must a household have in order to be in...

Average Daily TV Viewing Time Per U.S. Household Year Hours Min Total Min 1950 4 39...

Average Daily TV Viewing Time Per U.S. Household Year Hours Min Total Min 1950 4 39 279 1955 5 5 305 1960 5 33 333 1965 6 4 364 1970 6 38 398 1975 7 7 427 1980 7 45 465 1985 8 22 502 1990 8 7 487 1995 8 38 518 2000 9 2 542 2005 9 30 570 2010 9 41 581 Click here for the Excel Data File (a) Fit a...

Nielsen Media Research collects information on daily TV viewing time, in hours, and publishes it findings...

Nielsen Media Research collects information on daily TV viewing time, in hours, and publishes it findings in Time Spent Viewing. A random sample of daily viewing times for men, women, teens and children is obtained. The data are contained in the table below. a) Provide an appropriate graphical summary for the data. b) Do the data provide sufficient evidence to conclude that a difference exists among the means of the four view groups? Provide a formal hypothesis test as part...

According to the South Dakota Department of Health, the number of hours of TV viewing per...

According to the South Dakota Department of Health, the number of hours of TV viewing per week is higher among adult women than adult men. A recent study showed women spent an average of 33 hours per week watching TV, and men, 24 hours per week. Assume that the distribution of hours watched follows the normal distribution for both groups, and that the standard deviation among the women is 5.0 hours and is 5.9 hours for the men. What percent...

Assume that a population is normally distributed with a population mean of μ = 8 and...

Assume that a population is normally distributed with a population mean of μ = 8 and a population standard deviation of s = 2. [Notation: X ~ N(8,2) ] Use the Unit Normal Table to answer the following questions. (I suggest you draw a picture of the normal curve when answering these questions.) 8. Let X=4 Compute the z-score of X. For that z-score: a. What proportion of the area under the Unit Normal Curve is in the tail? b....

Assume that a population is normally distributed with a population mean of μ = 8 and...

Assume that a population is normally distributed with a population mean of μ = 8 and a population standard deviation of s = 2. [Notation: X ~ N(8,2) ] Use the Unit Normal Table to answer the following questions. (I suggest you draw a picture of the normal curve when answering these questions.) 8. Let X=7 Compute the z-score of X. For that z-score: a. What proportion of the area under the Unit Normal Curve is in the tail? b....

According to Nielsen Media Research, the average number of hours of TV viewing per household per...

According to Nielsen Media Research, the average number of hours of TV viewing per household per week in the United States is 50.4 hours. 1 (a) Suppose the population standard deviation is 11.8 hours and a random sample of 42 U.S. household is taken, what is the probability that the sample mean TV viewing time is between 47.5 and 52 hours? 1 (b) Suppose the population mean and sample size is still 50.4 hours and 42, respectively, but the population...

The daily selling price per 100 pounds of buffalo meat is normally distributed with a mean...

The daily selling price per 100 pounds of buffalo meat is normally distributed with a mean of 70 dollars, and the probability that the daily price is less than 85 dollars is 0.9332. Four days are chosen at random, what is the probability that at least one of the days has a price that exceeds 80 dollars?

8. Assume that adults have IQ scores that are normally distributed with a mean of 100...

8. Assume that adults have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 15 (as on the Wechsler test). Let X be the IQ scores for adults. So ( ) 2 X N~ 100,15 a. Find the probability that a randomly selected adult has an IQ greater than 131.5 (the requirement for membership in the Mensa organization). Show the area under the normal curve. b. Find the probability that a randomly selected...

Subjects