Question

1. 6) Which options below are true? [Enter your answer as a string of the letter options you believe are correct. For instance, if you think options A, D, and E are correct, then enter "ADE"]
   
   A) Particle 2's electric field contributes to the electric force on particle 1.
   B) Particle 1's electric field does not contribute to the electric force on particle 1.
   C) If particle 2 were removed, there would no longer be a non-zero electric field at its location.
   D) If particle 2's distance from particle 1 is tripled, particle 1's electric field at 2's new location is no different than before since the field does not depend on the the properties of particle 2.
   E) None of the above

(Please note that I put this question up already and they got AC and it was wrong. This does not include that CD are wrong, there can be more right answers, one can be wrong, or both).

Answer 1

Concept:

The region around the electric charge in which the stress or electric force act is called an electric field or electrostatic field.

electric force occurs between all charged particles. These very small particles are found inside atoms, and they are called protons and electrons. Each proton has a positive charge, and each electron has a negative charge. Protons and electrons are the smallest charged particles that exist. .
The strength of the electric force between any two charged objects depends on the amount of charge that each object contains and on the distance between the two charges. As the amount of charge gets bigger, the force gets bigger, and as the distance between the two charges gets larger, the force gets smaller. This is known as Coulomb's Law

A is correct

Because, particle 2s electric field applies force on particle one

Any charged particle placed in electric field experiences force.

B is also correct because

Self electric field never applies force on particle from where it has originated So self electric field do not produce force on its originator. electric field n particle 1 dosen´t affect at its own.

Now Coming Option C,

If particle 2 is removed then there will be non zero electric field due to charge 1

so option C is wrong.

Now coming to option D,

If distance is increased then at new location electric field will get reduced Because electric field decreases with distance

So option D is wrong statement.

So option ´AB´ is correct

ELE CTRIC FIELD (E E kQ E 2 P E = ko E 2

Here e = electiffeld K Qchasge charge adius

ELE CTRIC FIELD (E E kQ E 2 P E = ko E 2

Here e = electiffeld K Qchasge charge adius