Question

Write a Java program (name it LargestOccurenceCount) that reads from the user positive non-zero integer values, finds the largest value, and counts it occurrences. Assume that the input ends with number 0 (as sentinel value to stop the sentinel loop). The program should ignore any negative input and should continue to run.

Hint: to remember/save entered (good) values, you can concatenate them into a string (separated by spaces) that you can output later on.

Sample runs showing input prompts and outputs are (DO NOT read inputs as String type):

Enter positive integers (0 to quit): 3 4 5 -9 4 2 5 1 -5 2 5 0

You entered: 3 4 5 4 2 5 1 2 5

Largest value: 5

Occurrences: 3 times

Enter positive integers (0 to quit): 3 7 5 -4 4 2 -5 5 1 7 7 0

You entered: 3 7 5 4 2 5 1 7 7

Largest value: 7

Occurrences: 3 times

Document your code, and organize and space out your outputs as shown. Design your program such that it allows the user to re-run the program with different inputs in the same run (i.e., use a sentinel loop structure).

Answer 1

import java.util.Scanner;

public class LargestOccurenceCount {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        char ch;
        do {
            System.out.print("Enter positive integers (0 to quit): ");
            int largest = 0, count = 0, num;
            while (true) {
                num = in.nextInt();
                if (num == 0) {
                    break;
                } else if (num > largest) {
                    largest = num;
                    count = 1;
                } else if (num == largest) {
                    count++;
                }
            }
            System.out.println("Largest value:\t" + largest);
            System.out.println("Occurrences:\t" + count + " times");
            System.out.print("Do you want to try again(y or n): ");
            ch = in.next().charAt(0);
            System.out.println();
        } while (ch == 'y' || ch == 'Y');
    }
}