Question
In: Math
A survey showed that 79% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight....
A survey showed that 79% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 20 adults are randomly selected, find the probability that no more than 1 of them need correction for their eyesight. Is 1 a significantly low number of adults requiring eyesight correction? The probability that no more than 1 of the 20 adults require eyesight correction is nothing.
Solutions
milcah answered 8 months agoRelated Solutions
A survey showed that 78% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight....
A survey showed that 78% of adults need correction (eyeglasses,
contacts, surgery, etc.) for their eyesight. If 9 adults are
randomly selected, find the probability that at leastat least 8 of
them need correction for their eyesight. Is 8 a significantly
highhigh number of adults requiring eyesight correction?
A survey showed that 84% of adults need correction eyeglasses, contacts, surgery, etc.) for their eyesight...
A survey showed that 84% of adults need correction eyeglasses,
contacts, surgery, etc.) for their eyesight lf 9 adults are
randomly selected find the probability that no more than 1 of them
need correction for their eyesight. Is 1 a significantly low number
of adults requiring eyesight correction?
The probability that no more than 1 of the 9 adults require
eyesight correction is _____ (Round to three decimal places as
needed.)
Is 1 a significantly low number of adults requiring...
A survey showed that 75% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight....
A survey showed that
75%
of adults need correction (eyeglasses, contacts, surgery,
etc.) for their eyesight. If
1616
adults are randomly selected, find the probability that
no more thanno more than
1
of them need correction for their eyesight. Is
1
a significantly
lowlow
number of adults requiring eyesight correction?
The probability that
no more thanno more than
1
of the
16
adults require eyesight correction is
nothing .
(Round to three decimal places as needed.)
Is
1
a significantly...
In 2003 a survey of 35,000 adults showed that 26% were smokers. In 2010 a survey...
In 2003 a survey of 35,000 adults showed that 26% were smokers.
In 2010 a survey of 45,000 adults showed that 21% were smokers.
Construct a 95% confidence interval for the true difference between
proportions.
a) (4.41% , 5.59%)
b) (3.33% , 6.67%)
c) (4.82% , 5.18%)
d) (3.83% , 6.17%)
A recent survey of 1000 adults between 18 and 40 showed that 34% said they had...
A recent survey of 1000 adults between 18 and 40 showed that 34%
said they had no credit cards. Find the 99% confidence interval for
the population proportion.
{Exercise 3.29 (Algorithmic)} The results of a national survey showed that on average, adults sleep 6.9...
{Exercise 3.29
(Algorithmic)}
The results of a national survey showed that on average, adults
sleep 6.9 hours per night. Suppose that the standard deviation is 1
hours.
Round your answers to the nearest whole number.
Use Chebyshev's theorem to
calculate the percentage of individuals who sleep between 4.9 and
8.9 hours.
At least %
Use Chebyshev's theorem to
calculate the percentage of individuals who sleep between 3.9 and
9.9 hours.
At least %
Assume that the number of
hours of...
1. A survey about same-sex marriage used a random sample with 1200 adults. The results showed...
1. A survey about same-sex marriage used a random sample with
1200 adults. The results showed that
30% favored legal marriage, 32%
favored civil unions, and 38% favored no legal
recognition. Computer the right boundary at the 91% C.L. for the
proportion of adults who favor the “legal marriage” position.
2. A survey about same-sex marriage used a random sample with
1200 adults. The results showed that
30% favored legal marriage, 32%
favored civil unions, and 38% favored no legal...
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