Question

Given a list of negative integers, write a Python program to display each integer in the list that is evenly divisible by either 5 or 7. Also, print how many of those integers were found.

Sample input/output:

Enter a negative integer (0 or positive to end): 5
Number of integers evenly divisible by either 5 or 7: 0

Sample input/output:

Enter a negative integer (0 or positive to end): -5
-5 is evenly divisible by either 5 or 7.
Enter a negative integer (0 or positive to end): -35
-35 is evenly divisible by either 5 or 7.
Enter a negative integer (0 or positive to end): -3
Enter a negative integer (0 or positive to end): -7
-7 is evenly divisible by either 5 or 7.
Enter a negative integer (0 or positive to end): 0
Number of integers evenly divisible by either 5 or 7: 3

Answer 1

# Initializing count to zero
count = 0
# reading value of n from user
n = int(input("Enter a negative integer (0 or positive to end): "))
# Loop till n becomes zero
while(n!=0):
    # Checking n is divisible by 5 or 7
    if (n%5==0) or (n%7==0):
        # Incrementing count by 1
        count += 1
        # Printing message
        print(n,"is evenly divisible by either 5 or 7.")
    # reading value of n from user again
    n = int(input("Enter a negative integer (0 or positive to end): "))
# Printing Number of integers evenly divisible by either 5 or 7
print("Number of integers evenly divisible by either 5 or 7:",count)