Question

Minimum value and its position

Create a program that:

• Receive as input in command line the sizes m and n of a two dimensional array, and minValue and maxValue between which the random numbers will be generated
• Generate a array with numbers between minValue and maxValue (inclusive) with the given size (mxn)
• Compute the minimum value in the array and one of the rows and columns on which it appears.
• Print the array as a table.
• Print the minimum value and one of the positions on which it appears.

Run the program 5 times with representative sizes

Answer 1

Since you have not provided the language of your preference, I am providing the code in Java.

CODE

import java.util.Random;

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

int m, n, minValue, maxValue;

System.out.println("Enter the value of m and n: ");

m = sc.nextInt();

n = sc.nextInt();

System.out.println("Enter the value of minValue and maxValue: ");

minValue = sc.nextInt();

maxValue = sc.nextInt();

Random rand = new Random();

int[][] arr = new int[m][n];

for (int i=0; i<m; i++) {

for (int j=0; j<n; j++) {

arr[i][j] = rand.nextInt(maxValue - minValue + 1) + minValue;

}

}

int min = Integer.MAX_VALUE;

int minRow = -1, minColumn = -1;

for (int i=0; i<m; i++) {

for (int j=0; j<n; j++) {

if (arr[i][j] < min) {

min = arr[i][j];

minRow = i;

minColumn = j;

}

}

}

System.out.println("The array is: ");

for (int i=0; i<m; i++) {

for (int j=0; j<n; j++) {

System.out.print(arr[i][j] + " ");

}

System.out.println();

}

System.out.println("The minimum value is: " + min + " which is present at location (" + minRow + ", " + minColumn + ")");

}

}