Question

Modify program so that input comes in as command line arguments.
Sample run:
./a.out W8 4 ME 2 finish 2!
Output:
Consonants: WMfnsh


1) Name your program command_consonants.c.

2) If no command line arguments was provided, your program should print a usage message “Usage: ./a.out input

#include<stdio.h>

int main()
{
printf("Input: ");
int i = 0;
char ch;
// array to store consonants
char consonant[100]={""};
//do loop to take input
do
{
ch = getchar();
//checks to see if consonants or not
if(((ch >= 'a' && ch <= 'z')||(ch >= 'A' && ch <= 'Z')) && !(ch == 'a' || ch == 'e' || ch == 'i'|| ch == '0' || ch == 'u' || ch == 'A' || ch =='E'|| ch=='I' || ch =='O' || ch == 'U'))
{
consonant[i] = ch;
i++;
}
  
}
while(ch != '\n');
  
printf("Consonants:");
printf("%s", consonant);
  
return 0;
}

Answer 1

CODE -

#include<stdio.h>

int main(int argc, char* argv[])

{

    int i = 0;

    char ch;

    // array to store consonants

    char consonant[100]={""};

    // Printing usage message if no command line arguments was provided.

    if(argc==1)

        printf("Usage: ./a.out input");

    // Iterating over each space seperated string in the command line input

    for(int j=1; j<argc; j++)

    {

        int k=0;

        // do loop to read character by character of the strings in command line input

        do

        {

            ch = argv[j][k];

            //checks to see if consonants or not

            if(((ch >= 'a' && ch <= 'z')||(ch >= 'A' && ch <= 'Z')) && !(ch == 'a' || ch == 'e' || ch == 'i'|| ch == '0' || ch == 'u' || ch == 'A' || ch =='E'|| ch=='I' || ch =='O' || ch == 'U'))

            {

                consonant[i] = ch;

                i++;

            }

            k++;

        }while(ch != '\0');

    }

    

    printf("Consonants: ");

    printf("%s", consonant);

    

    return 0;

}

SCREENSHOT -

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