In: Finance
Consider a 1-year option with exercise price $85 on a stock with annual standard deviation 10%. The T-bill rate is 2% per year. Find N(d1) for stock prices $80, $85, and $90. (Do not round intermediate calculations. Round your answers to 4 decimal places.)
| S | N(d1) |
| $80 | |
| $85 | |
| $90 | |
|
S |
N(d1) |
|
$80 |
0.3608 |
|
$85 |
0.5987 |
|
$90 |
0.7943 |
Notations:
|
S = Stock price |
|
K = Strike price |
|
r = rate |
|
e = exponential value = exp(.) |
|
t = time |
|
s = standard deviation or volatility |
* N(d1) is Normal distribution probability value for calculated d1
1.
d1 = (Ln(S/(K*exp(-r*t))+0.5*s^2*t)/(s*t^0.5)
=(LN(80/((85*EXP(-0.02*1))))+0.5*0.1^2*1)/(0.1*1^0.5)
d2 = -0.356246 Hence, N(d1) = 0.3608
2.
d1 = (Ln(S/(K*exp(-r*t))+0.5*s^2*t)/(s*t^0.5)
=(LN(85/((85*EXP(-0.02*1))))+0.5*0.1^2*1)/(0.1*1^0.5)
d2 = 0.250000 Hence, N(d1) = 0.5987
3.
d1 = (Ln(S/(K*exp(-r*t))+0.5*s^2*t)/(s*t^0.5)
=(LN(90/((85*EXP(-0.02*1))))+0.5*0.1^2*1)/(0.1*1^0.5)
d2 = 0.821584 Hence, N(d1) = 0.7943