In: Physics
A charge of q = 4.00 ✕ 10−9 C is spread evenly on a thin metal disk of radius 0.160 m. HINT (a) Calculate the charge density (in C/m2) on the disk. C/m2 (b) Find the magnitude of the electric field (in N/C) just above the center of the disk, neglecting edge effects and assuming a uniform distribution of charge. N/C
Given data:
Charge on thin metal disk = 4 x 10-9 C
Radius of the disk = 0.160 m
Answer a)
Charge density of the disc will be given by:
Where q is the charge on the disk
r is the radius of the disk
Which is the required answer
Answer b)
Electric field due to a thin circular disk is given by:
Where is the surface charge density
is the absolute permittivity
R is the radius of the disk
x is the distance from the center of the disk where electric field measurement is being made
For electric field just above the center of the disk . Therefore above formula takes the form:
Substituting the values in above formula we get:
Which is the required answer
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