use laplace to answer y"-3y'+2y=1+cost+e^-t,y(0)=1,y'(0)=0

Expert Solution

Colby Messinger answered 2 years ago

y''-3y+2y=e^3t y(0)=1 y'(0)=0 laplace transformation

y''-3y'+2y=1+cost+e^-t

Solve the differential equation by Laplace transform y^(,,) (t)-2y^' (t)-3y(t)=sint where y^' (0)=0 ,y=(0)=0

y''+ 3y'+2y=e^t y(0)=1 y'(0)=-6 Solve using Laplace transforms. Then, solve using undetermined coefficients. Then, solve using...

y''+ 3y'+2y=e^t y(0)=1 y'(0)=-6 Solve using Laplace transforms. Then, solve using undetermined coefficients. Then, solve using variation of parameters.

Laplace Question : y''-3y'+2y=4cos2t,y(0)=-2,y'(0)=0

u(t−c) =uc(t) ={0, 0≤t<c,1, t≥c.} USE Laplace Transform to solve y′′+ 2y′+ 2y=δ(t−5)e^tcost, y(0) = 1,...

u(t−c) =uc(t) ={0, 0≤t<c,1, t≥c.} USE Laplace Transform to solve y′′+ 2y′+ 2y=δ(t−5)e^tcost, y(0) = 1, y′(0) = 2, whereδ(t)is the Dirac delta. Does the solution show a resonance?

Solve the differential equation using the Laplace transform. y''' + 3y''+2y' = 100e-t , y(0) =...

Solve the differential equation using the Laplace transform. y''' + 3y''+2y' = 100e-t , y(0) = 0, y'(0) = 0, y''(0) = 0

y'' - y = e^(-t) - (2)(t)(e^(-t)) y(0)= 1 y'(0)= 2 Use Laplace Transforms to solve....

y'' - y = e^(-t) - (2)(t)(e^(-t)) y(0)= 1 y'(0)= 2 Use Laplace Transforms to solve. Sketch the solution or use matlab to show the graph.

Use the Laplace transform to solve the problem with initial values y''-2y'+2y=cost y(0)=1 y'(0)=0

Use the Laplace transform to solve the given initial value problem: y''+3y'+2y=1 y(0)=0, y'(0)=2

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