using the Laplace transform solve the IVP
y'' +4y= 3sin(t) y(0) =1 , y'(0) = - 1 , i am stuck on the
partial fraction decomposition step. please explain the
decomposition clearly.
Use the Laplace transform to find the solution of the IVP:
a.) 2y' + y = 1, y(0) = 2 (answer should be y(t) = 1 + e-t
/ 2 )
f.) 4y" + y = 0, y(0) = -1, y'(0) = -1 (answer should be y(t) =
-sin(t) - cos(t))
Please show work!