Question

In: Math

The effect of applying x milligrams of drug A and y milligrams of drug B is measured by

The effect of applying x milligrams of drug A and y milligrams of drug B is measured by

 f(x, y) = xy - 2x2 - y2 + 120x + 40y + 25

 

What amounts of each drug should be used to get the biggest effect?

 

Solutions

Expert Solution

The effect of applying x milligrams of drug A and y milligrams of drug B is measured by the function

The first and second order partial derivatives of this function are

The stationary points can be found by solving the below system of equations.

From the above system of equations, we get

Substituting the value of y, we get

Hence, the only stationary point is (40, 40).

For this stationary point,

Hence, the amounts of each drug that should be used to get the biggest effect are


Related Solutions

AND( OR(OR(X,Y), AND(OR(X,Y), OR(NOT(X), NOT(Y)))), OR(OR(X,Y), AND(OR(X,Y), NAND(X,Y))) ) is equivalent to: A. OR(X,Y) B. AND(X,Y)...
AND( OR(OR(X,Y), AND(OR(X,Y), OR(NOT(X), NOT(Y)))), OR(OR(X,Y), AND(OR(X,Y), NAND(X,Y))) ) is equivalent to: A. OR(X,Y) B. AND(X,Y) C. NOR(X,Y) D. XOR(X,Y) E. NAND(X,Y) F. XNOR(X,Y) How do I simplify this with the Idempotence, De morgan, absorbtion law, etc and waht are the steps to break it down?
Let X and Y equal the number of milligrams of tar in filtered and nonfiltered cigarettes,...
Let X and Y equal the number of milligrams of tar in filtered and nonfiltered cigarettes, respectively. Assume that ?~?(??, ?2) and ?~?(??, ?2). We shall test the null hypothesis ?0: ?? = ?? against the alternative hypothesis ??: ?? < ?? using independent random samples of sizes n = 9 and m = 11 observations from X and Y, respectively. Define the test statistic for testing the above hypothesis, and the rejection region that is associated with an ?...
Prove that The OR operation is closed for all x, y ∈ B x + y ∈ B
Boolean AlgebraProve that The OR operation is closed for all x, y ∈ B x + y ∈ BandProve that The And operation is closed for all x, y ∈ B x . y ∈ B
That is, PDEs of the general form A(x, y, u) ∂u(x, y) ∂x + B(x, y,...
That is, PDEs of the general form A(x, y, u) ∂u(x, y) ∂x + B(x, y, u) ∂u(x, y) ∂y = C(x, y, u), (1) for some A, B and C. To solve such PDEs we first find characteristics, curves in the solution space (x, y, u) parametrically given by (x(τ ), y(τ ), u(τ )), which satisfy dx dτ = A(x, y, u), dy dτ = b(x, y, u), du dτ = C(x, y, u). (2) We find solutions...
a) y''(x)-3y'(x)=8e3x+4sinx b) y''(x)+y'(x)+y(x)=0 c) y(iv)(x)+2y''(x)+y(x)=0
a) y''(x)-3y'(x)=8e3x+4sinx b) y''(x)+y'(x)+y(x)=0 c) y(iv)(x)+2y''(x)+y(x)=0
Question A2 Both Drug A and Drug B produce similar therapeutic effect for treatment of cardiac...
Question A2 Both Drug A and Drug B produce similar therapeutic effect for treatment of cardiac arrhythmias. The ED50 and TD50 of Drug A are 200mg and 1g respectively, whereas the ED50 of Drug B is 250mg with a TD50 of 2g. (a) Calculate the therapeutic index (TI) of these two drugs. (b) Determine which drug is safer for administration and clearly explain your answer.
The concentration of benzene was measured in units of milligrams per liter for a smiple random...
The concentration of benzene was measured in units of milligrams per liter for a smiple random sample of 10 specimans of untreated wastewater produced at a gas field. The sample had an average of 7.15 with a standard deviation of 1.01. Another simple random sample of 6 specimans of treated wastewater had an average of 3.1 with a standard deviation of 1.65. It has been confirmed that both samples come from a normal distribution. Can you conclude that the true...
The concentration of benzene was measured in units of milligrams per liter for a smiple random...
The concentration of benzene was measured in units of milligrams per liter for a smiple random sample of 10 specimans of untreated wastewater produced at a gas field. The sample had an average of 7.15 with a standard deviation of 1.01. Another simple random sample of 6 specimans of treated wastewater had an average of 3.1 with a standard deviation of 1.65. It has been confirmed that both samples come from a normal distribution. Can you conclude that the true...
Contaminated water: The concentration of benzene was measured in units of milligrams per liter for a...
Contaminated water: The concentration of benzene was measured in units of milligrams per liter for a simple random sample of five specimens of untreated wastewater produced at a gas field. The sample mean was 7.8 with a sample standard deviation of 3.1. Seven specimens of treated wastewater had an average benzene concentration of 3.7 with a standard deviation of 2.5. It is reasonable to assume that both samples come from populations that are approximately normal. Can you conclude that the...
Contaminated water: The concentration of benzene was measured in units of milligrams per liter for a...
Contaminated water: The concentration of benzene was measured in units of milligrams per liter for a simple random sample of five specimens of untreated wastewater produced at a gas field. The sample mean was 3.7 with a sample standard deviation of 1.8. Seven specimens of treated wastewater had an average benzene concentration of 7.2 with a standard deviation of 3. It is reasonable to assume that both samples come from populations that are approximately normal. Can you conclude that the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT