Question

C++

Text message decoder

Use getline() to get a line of user input into a string:

Enter text:  
IDK if I'll go. It's my BFF's birthday. 

Search the string using find() for common abbreviations and replace() them with their long form. In addition, use a for loop to iterate through each character of the string and replace any occurences of '.' with '!':

Enter text:
IDK if I'll go.  It's my BFF's birthday. 

I don't know if I'll go!  It's my best friend forever's birthday!

Use loops for each abbreviation to replace multiple occurrences:

Enter text:
Hi BFF.  IDK where I'm going but it's not going to be with you!  JK you know you're my BFF.  IDK why I just said that.  Anyway, TMI.  Why do I always give people TMI?  IDK.  Alright TTYL bye BFF!

Hi best friend forever!  I don't know where I'm going but it's not going to be with you!  just kidding you know you're my best friend forever!  I don't know why I just said that!  Anyway, too much information!  Why do I always give people too much information!  I don't know!  Alright talk to you later bye best friend forever!

Support these abbreviations:

• BFF -- best friend forever
• IDK -- I don't know
• JK -- just kidding
• TMI -- too much information
• TTYL -- talk to you later

Use the predefined constants for each abbreviation BFF, IDK, etc. and each long form BFF_LONG, IDK_LONG, etc. rather than hardcoding strings inside the loop.

Answer 1

// do comment if any problem arises

//code

#include <iostream>

#include <string>

using namespace std;

// SHORT

const string BFF = "BFF";

const string IDK = "IDK";

const string JK = "JK";

const string TMI = "TMI";

const string TTYL = "TTYL";

// LONG

const string BFF_LONG = "best friend forever";

const string IDK_LONG = "I don't know";

const string JK_LONG = "just kidding";

const string TMI_LONG = "too much information";

const string TTYL_LONG = "talk to you later";

int main()

{

    cout << "Enter text:\n";

    string input;

    getline(cin, input);

    // run till there are no abreviations left

    while (true)

    {

        // for BBF

        if (input.find(BFF) != string::npos)

        {

            input.replace(input.find(BFF), 3, BFF_LONG);

        }

        // for JDK

        else if (input.find(IDK) != string::npos)

        {

            input.replace(input.find(IDK), 3, IDK_LONG);

        }

        // for JK

        else if (input.find(JK) != string::npos)

        {

            input.replace(input.find(JK), 2, JK_LONG);

        }

        // for TMI

        else if (input.find(TMI) != string::npos)

        {

            input.replace(input.find(TMI), 3, TMI_LONG);

        }

        // for TTYL

        else if (input.find(TTYL) != string::npos)

        {

            input.replace(input.find(TTYL), 4, TTYL_LONG);

        }

        // if none left then break

        else

            break;

    }

    // print final string

    cout << endl

         << input;

}

Output: