Question
In: Statistics and Probability
A simple random sample from a population with a normal distribution of 98 body temperatures has...
A simple random sample from a population with a normal distribution of 98 body temperatures has a mean of 98.50degrees F and a standard deviation of 0.67degrees F. Construct a 99?% confidence interval estimate of the standard deviation of body temperature of all healthy humans. Is it safe to conclude that the population standard deviation is less than 2.30degrees F?? LOADING... Click the icon to view the table of? Chi-Square critical values.
Solutions
Expert Solution
At 99% confidence interval the critical values are 
= 136.62
= 64.88
The 99% confidence interval for 
is
sqrt((n - 1)s^2/)
<
< sqrt((n - 1)s^2/)
= sqrt(97 * (0.68)^2/136.62) <
< sqrt(97 * (0.68)^2/64.88)
= 0.573 <
< 0.831
Yes it can be conclude that the population standard deviation is less than 2.30 degrees F.
orchestra answered 2 years agoRelated Solutions
A simple random sample from a population with a normal distribution of 98 body temperatures has...
A simple random sample from a population with a normal
distribution of 98 body temperatures has x overbar=98.80degrees
Upper F and s=0.67degrees Upper F. Construct a 95% confidence
interval estimate of the standard deviation of body temperature of
all healthy humans.
A simple random sample from a population with a normal distribution of 108 body temperatures has...
A simple random sample from a population with a normal
distribution of 108 body temperatures has x = 98.30 degrees F° and
s = 0.68 degrees F°
Construct a 95% confidence interval estimate of the standard
deviation of body temperature of all healthy humans.
(Round to two decimal places as needed.)
A simple random sample from a population with a normal distribution of 109 body temperatures has...
A simple random sample from a population with a normal
distribution of 109 body temperatures has x = 98.50 degrees Upper F
and s =0.69degrees Upper F. Construct a 90% confidence interval
estimate of the standard deviation of body temperature of all
healthy humans.
____ degree F < o <____ degree F
A simple random sample from a population with a normal distribution of 108 body temperatures has...
A simple random sample from a population with a normal
distribution of 108 body temperatures has x
overbarequals98.50degrees Upper F and sequals0.62degrees Upper F.
Construct a 90% confidence interval estimate of the standard
deviation of body temperature of all healthy humans.
A simple random sample from a population with a normal distribution of 99 body temperatures has...
A simple random sample from a population with a normal
distribution of 99 body temperatures has x
overbarequals98.20degrees Upper F and sequals0.64degrees Upper F.
Construct a 90% confidence interval estimate of the standard
deviation of body temperature of all healthy humans. LOADING...
Click the icon to view the table of Chi-Square critical values.
nothingdegrees Upper Fless thansigmaless than nothingdegrees Upper
F (Round to two decimal places as needed.)
A simple random sample from a population with a normal distribution of 109 body temperatures has...
A simple random sample from a population with a normal
distribution of 109
body temperatures has x overbar=99.10degrees Upper F°and
=0.65F°
Construct A 98% confidence interval estimate of the standard
deviation of body temperature of all healthy humans.
Click the icon to view the table of Chi-Square critical
values.
F°<sigmaσless than<F
A simple random sample from a population with a normal distribution of 100 body temperatures has...
A simple random sample from a population with a normal
distribution of 100 body temperatures has x overbar equals 99.10
degrees and s equals 0.65 degrees Construct an 80% confidence
interval estimate of the standard deviation of body temperature of
all healthy humans.
A simple random sample from a population with a normal distribution of 109 body temperatures has...
A simple random sample from a population with a normal
distribution of 109 body temperatures has x=98.10 degrees F and
s=0.67° F.
Construct a 99% confidence interval estimate of the standard
deviation of body temperature of all healthy humans.
A simple random sample from a population with a normal distribution of 9797 body temperatures has...
A simple random sample from a population with a normal
distribution of
9797
body temperatures has
x overbarxequals=98.7098.70degrees Upper F°F
and
sequals=0.670.67degrees Upper F°F.
Construct
a
99%
confidence interval estimate of the standard deviation of body
temperature of all healthy humans.
A simple random sample from a population with a normal distribution of 100 body temperatures has...
A simple random sample from a population with a normal
distribution of 100 body temperatures has a mean of 98.40 and
s=0.68 degree F. Construct a 90% confidence interval.
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- Calculate the ideal age of a spouse. Enter either m or f from the keyboard in...
- Due to a recession, expected inflation this year is only 4.75%. However, the inflation rate in...
- What are the benefits of doing a pilot program before a full scale rollout of a...
- It is a calm summer day in southeast Iowa at the Ottumwa air traffic control radar...
- 1. Write a detailed article on Evolution of attacks on the internet & web [your article...
- Analyze the role of the contingency plan coordinator (CPC) in the scope of preparing a BIA....
- Amazing Manufacturing, Inc., has been considering the purchase of a new manufacturing facility for $500,000. The...
ADVERTISEMENT